What is the general solution for cos(x)-cos(2x)=0,0<= x<360 ?

The general solution for cos(x)-cos(2x)=0,0<= x<360 is x=0,x=120,x=240

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cos(x)-cos(2x)=0,0<= x<360

cos (x) - cos (2 x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

x = 0, x = 12 0^{\circ}, x = 24 0^{\circ}

Solution steps

cos (x) - cos (2 x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

Rewrite using trig identities

2 sin (\frac{3 x}{2}) sin (\frac{x}{2}) = 0

Solving each part separately

sin (\frac{3 x}{2}) = 0 or sin (\frac{x}{2}) = 0

sin (\frac{3 x}{2}) = 0, 0 \leq x < 36 0^{\circ} : x = 0, x = 12 0^{\circ}, x = 24 0^{\circ}

sin (\frac{x}{2}) = 0, 0 \leq x < 36 0^{\circ} : x = 0

Combine all the solutions

x = 0, x = 12 0^{\circ}, x = 24 0^{\circ}

3 = - 3 cos (θ)

2 cos (θ) - 3 = 0, 0 \leq θ \leq 2 π

- 4 sin (x) = cos^{2} (x) + 1, 0 \leq x \leq 2 π

3 sin (x) - 3 cos (x) = 3

tan (2 x) cos (2 x) + cot (2 x) sin (2 x) = 1

What is the general solution for cos(x)-cos(2x)=0,0<= x<360 ?
The general solution for cos(x)-cos(2x)=0,0<= x<360 is x=0,x=120,x=240