What is the general solution for sin(θ)=0.7cos(90-θ) ?

The general solution for sin(θ)=0.7cos(90-θ) is θ=360n,θ=180+360n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=0.7cos(90-θ)

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

θ = 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

Rewrite using trig identities

sin (θ) = 0.7 sin (θ)

Subtract

0.7 sin (θ)

from both sides

0.3 sin (θ) = 0

Multiply both sides by

10

3 sin (θ) = 0

Divide both sides by

3

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

Solve

θ = 0 + 36 0^{\circ} n : θ = 36 0^{\circ} n

θ = 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

cos (θ) = \frac{4}{2}

2 sin^{2} (x) = 4 sin (x) + 6, (0, 2 π)

2 cos (3 x + 2 0^{\circ}) = 2

cot^{2} (3 x) - 2 cot (3 x) + 1 = 0

- \frac{tanh ( n x )}{cosh ( n x )} = 0

What is the general solution for sin(θ)=0.7cos(90-θ) ?
The general solution for sin(θ)=0.7cos(90-θ) is θ=360n,θ=180+360n