What is the general solution for cos(A)+1=4cos(A)+1 ?

The general solution for cos(A)+1=4cos(A)+1 is A= pi/2+2pin,A=(3pi)/2+2pin

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cos(A)+1=4cos(A)+1

cos (A) + 1 = 4 cos (A) + 1

A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

Solution steps

cos (A) + 1 = 4 cos (A) + 1

Solve by substitution

cos (A) = 0

cos (A) = 0 : A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

Combine all the solutions

A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

3 cos (x) + 2 = 0

sin (θ) = 0.7 cos (9 0^{\circ} - θ)

cos (θ) = \frac{4}{2}

2 sin^{2} (x) = 4 sin (x) + 6, (0, 2 π)

2 cos (3 x + 2 0^{\circ}) = 2

What is the general solution for cos(A)+1=4cos(A)+1 ?
The general solution for cos(A)+1=4cos(A)+1 is A= pi/2+2pin,A=(3pi)/2+2pin