What is the general solution for 3tan(2θ)-sqrt(3)=0 ?

The general solution for 3tan(2θ)-sqrt(3)=0 is θ= pi/(12)+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3tan(2θ)-sqrt(3)=0

3 tan (2 θ) - 3 = 0

θ = \frac{π}{12} + \frac{πn}{2}

Solution steps

3 tan (2 θ) - 3 = 0

Move

3

to the right side

3 tan (2 θ) = 3

Divide both sides by

3

tan (2 θ) = \frac{3}{3}

General solutions for

tan (2 θ) = \frac{3}{3}

2 θ = \frac{π}{6} + πn

Solve

2 θ = \frac{π}{6} + πn : θ = \frac{π}{12} + \frac{πn}{2}

θ = \frac{π}{12} + \frac{πn}{2}

cos (θ) = \frac{4 k - 1}{3}

5 sin (x) - 4 = 0

tan^{2} (θ) - 2 tan (θ) - 3 = 0

cos^{3} (x) + sin^{2} (x) \cdot cos (x) = - \frac{1}{2}

cos (3 A) + sin (A) = 0

What is the general solution for 3tan(2θ)-sqrt(3)=0 ?
The general solution for 3tan(2θ)-sqrt(3)=0 is θ= pi/(12)+(pin)/2