What is the general solution for tan^2(θ)-2tan(θ)-3=0 ?

The general solution for tan^2(θ)-2tan(θ)-3=0 is θ=1.24904…+pin,θ=(3pi)/4+pin

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tan^2(θ)-2tan(θ)-3=0

tan^{2} (θ) - 2 tan (θ) - 3 = 0

θ = 1.24904 \dots + πn, θ = \frac{3 π}{4} + πn

Solution steps

tan^{2} (θ) - 2 tan (θ) - 3 = 0

Solve by substitution

tan (θ) = 3, tan (θ) = - 1

tan (θ) = 3 : θ = arctan (3) + πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = arctan (3) + πn, θ = \frac{3 π}{4} + πn

Show solutions in decimal form

θ = 1.24904 \dots + πn, θ = \frac{3 π}{4} + πn

cos^{3} (x) + sin^{2} (x) \cdot cos (x) = - \frac{1}{2}

cos (3 A) + sin (A) = 0

0 = 1 - sec^{2} (x)

sin (θ) = 0.1

\frac{2}{sin ( x )} + 10 = 6

What is the general solution for tan^2(θ)-2tan(θ)-3=0 ?
The general solution for tan^2(θ)-2tan(θ)-3=0 is θ=1.24904…+pin,θ=(3pi)/4+pin