What is the general solution for sin(2x+20)-1=(-1)/2 ?

The general solution for sin(2x+20)-1=(-1)/2 is x=-10+pin+pi/(12),x=-10+pin+(5pi)/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Trigonometry >

sin(2x+20)-1=(-1)/2

Solution

sin (2 x + 20) - 1 = \frac{- 1}{2}

Solution

x = - 10 + πn + \frac{π}{12}, x = - 10 + πn + \frac{5 π}{12}

Degrees

x = - 557.95779 \dots^{\circ} + 18 0^{\circ} n, x = - 497.95779 \dots^{\circ} + 18 0^{\circ} n

Solution steps

sin (2 x + 20) - 1 = \frac{- 1}{2}

Move

1

to the right side

sin (2 x + 20) - 1 = \frac{- 1}{2}

Add

1

to both sides

sin (2 x + 20) - 1 + 1 = \frac{- 1}{2} + 1

Simplify

sin (2 x + 20) - 1 + 1 = \frac{- 1}{2} + 1

Simplify

sin (2 x + 20) - 1 + 1 : sin (2 x + 20)

sin (2 x + 20) - 1 + 1

Add similar elements:

- 1 + 1 = 0

= sin (2 x + 20)

Simplify

\frac{- 1}{2} + 1 : \frac{1}{2}

\frac{- 1}{2} + 1

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2} + 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 - 1}{2}

1 \cdot 2 - 1 = 1

1 \cdot 2 - 1

Multiply the numbers:

1 \cdot 2 = 2

= 2 - 1

Subtract the numbers:

2 - 1 = 1

= 1

= \frac{1}{2}

sin (2 x + 20) = \frac{1}{2}

sin (2 x + 20) = \frac{1}{2}

sin (2 x + 20) = \frac{1}{2}

General solutions for

sin (2 x + 20) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x + 20 = \frac{π}{6} + 2 πn, 2 x + 20 = \frac{5 π}{6} + 2 πn

2 x + 20 = \frac{π}{6} + 2 πn, 2 x + 20 = \frac{5 π}{6} + 2 πn

Solve

2 x + 20 = \frac{π}{6} + 2 πn : x = - 10 + πn + \frac{π}{12}

2 x + 20 = \frac{π}{6} + 2 πn

Move

20

to the right side

2 x + 20 = \frac{π}{6} + 2 πn

Subtract

20

from both sides

2 x + 20 - 20 = \frac{π}{6} + 2 πn - 20

Simplify

2 x = \frac{π}{6} + 2 πn - 20

2 x = \frac{π}{6} + 2 πn - 20

Divide both sides by

2

2 x = \frac{π}{6} + 2 πn - 20

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2} : - 10 + πn + \frac{π}{12}

\frac{\frac{π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Group like terms

= - \frac{20}{2} + \frac{2 πn}{2} + \frac{\frac{π}{6}}{2}

\frac{20}{2} = 10

\frac{20}{2}

Divide the numbers:

\frac{20}{2} = 10

= 10

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

= - 10 + πn + \frac{π}{12}

x = - 10 + πn + \frac{π}{12}

x = - 10 + πn + \frac{π}{12}

x = - 10 + πn + \frac{π}{12}

Solve

2 x + 20 = \frac{5 π}{6} + 2 πn : x = - 10 + πn + \frac{5 π}{12}

2 x + 20 = \frac{5 π}{6} + 2 πn

Move

20

to the right side

2 x + 20 = \frac{5 π}{6} + 2 πn

Subtract

20

from both sides

2 x + 20 - 20 = \frac{5 π}{6} + 2 πn - 20

Simplify

2 x = \frac{5 π}{6} + 2 πn - 20

2 x = \frac{5 π}{6} + 2 πn - 20

Divide both sides by

2

2 x = \frac{5 π}{6} + 2 πn - 20

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{5 π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{5 π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{5 π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2} : - 10 + πn + \frac{5 π}{12}

\frac{\frac{5 π}{6}}{2} + \frac{2 πn}{2} - \frac{20}{2}

Group like terms

= - \frac{20}{2} + \frac{2 πn}{2} + \frac{\frac{5 π}{6}}{2}

\frac{20}{2} = 10

\frac{20}{2}

Divide the numbers:

\frac{20}{2} = 10

= 10

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{5 π}{6}}{2} = \frac{5 π}{12}

\frac{\frac{5 π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{5 π}{12}

= - 10 + πn + \frac{5 π}{12}

x = - 10 + πn + \frac{5 π}{12}

x = - 10 + πn + \frac{5 π}{12}

x = - 10 + πn + \frac{5 π}{12}

x = - 10 + πn + \frac{π}{12}, x = - 10 + πn + \frac{5 π}{12}

Graph

Popular Examples

solvefor x,sin(x+pi/2)-cos^2(x)=0

0=4+3cos(θ)

cos(θ)= 6/8

solvefor x,4cos(x)*sin(y)=1

arctan(1/4 x)-pi-arctan(x/(100))=-pi

Frequently Asked Questions (FAQ)

What is the general solution for sin(2x+20)-1=(-1)/2 ?
The general solution for sin(2x+20)-1=(-1)/2 is x=-10+pin+pi/(12),x=-10+pin+(5pi)/(12)