cos(θ)=(-0.68159)

解答

cos (θ) = (- 0.68159)

θ = 2.32072 \dots + 2 πn, θ = - 2.32072 \dots + 2 πn

度数

θ = 132.96801 \dots^{\circ} + 36 0^{\circ} n, θ = - 132.96801 \dots^{\circ} + 36 0^{\circ} n

求解步骤

cos (θ) = (- 0.68159)

使用反三角函数性质

cos (θ) = - 0.68159

cos (θ) = - 0.68159

的通解

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- 0.68159) + 2 πn, θ = - arccos (- 0.68159) + 2 πn

θ = arccos (- 0.68159) + 2 πn, θ = - arccos (- 0.68159) + 2 πn

以小数形式表示解

θ = 2.32072 \dots + 2 πn, θ = - 2.32072 \dots + 2 πn

cot (x + \frac{5 π}{6}) = 3

so l v e f or θ, y = sin (θ)

sec^{2} (x) - 4 tan^{2} (x) = 0

6 cos^{2} (x) + cos (2 x) = 5

tanh (m L) = 0.99