What is the general solution for cos^3(θ)+cos^2(θ)-cos(θ)-1=0 ?

The general solution for cos^3(θ)+cos^2(θ)-cos(θ)-1=0 is θ=pi+2pin,θ=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^3(θ)+cos^2(θ)-cos(θ)-1=0

cos^{3} (θ) + cos^{2} (θ) - cos (θ) - 1 = 0

θ = π + 2 πn, θ = 2 πn

Solution steps

cos^{3} (θ) + cos^{2} (θ) - cos (θ) - 1 = 0

Solve by substitution

cos (θ) = - 1, cos (θ) = 1

cos (θ) = - 1 : θ = π + 2 πn

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = π + 2 πn, θ = 2 πn

2 sin^{2} (x) - 2 sin (x) = 0

9 sin^{2} (x) - 6 sin (x) + 1 = 0

y, ln (x) = arctan (\frac{y}{x})

cos (a) + 1 = 4 cos (a) + 1

6 cos (x) + 3 sin (x) = 5

What is the general solution for cos^3(θ)+cos^2(θ)-cos(θ)-1=0 ?
The general solution for cos^3(θ)+cos^2(θ)-cos(θ)-1=0 is θ=pi+2pin,θ=2pin