What is the general solution for 7cos(b)-sqrt(13)=0 ?

The general solution for 7cos(b)-sqrt(13)=0 is b=1.02969…+2pin,b=2pi-1.02969…+2pin

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7cos(b)-sqrt(13)=0

7 cos (b) - 13 = 0

b = 1.02969 \dots + 2 πn, b = 2 π - 1.02969 \dots + 2 πn

Solution steps

7 cos (b) - 13 = 0

Move

13

to the right side

7 cos (b) = 13

Divide both sides by

7

cos (b) = \frac{13}{7}

Apply trig inverse properties

b = arccos (\frac{13}{7}) + 2 πn, b = 2 π - arccos (\frac{13}{7}) + 2 πn

Show solutions in decimal form

b = 1.02969 \dots + 2 πn, b = 2 π - 1.02969 \dots + 2 πn

cos (θ) = \frac{6}{3.92739}

sin (x) = - \frac{1}{3}, 0 \leq x \leq 2 π

3 csc (x) = 2 tan (x)

3 = 6 cos (x)

2 cos (a) \cdot sin (2 a) - 1 + 2 sin (2 a) - cos (a) = 0

What is the general solution for 7cos(b)-sqrt(13)=0 ?
The general solution for 7cos(b)-sqrt(13)=0 is b=1.02969…+2pin,b=2pi-1.02969…+2pin