What is the general solution for solvefor θ,(90^2)/(250(32.2))=tan(θ) ?

The general solution for solvefor θ,(90^2)/(250(32.2))=tan(θ) is θ=0.78849…+pin

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solvefor θ,(90^2)/(250(32.2))=tan(θ)

solve for

θ, \frac{9 0 ^{2}}{250 ( 32.2 )} = tan (θ)

θ = 0.78849 \dots + πn

Solution steps

\frac{9 0 ^{2}}{250 ( 32.2 )} = tan (θ)

Switch sides

tan (θ) = \frac{9 0 ^{2}}{250 \cdot 32.2}

Simplify

\frac{9 0 ^{2}}{250 \cdot 32.2} : \frac{162}{161}

Apply trig inverse properties

θ = arctan (\frac{162}{161}) + πn

Show solutions in decimal form

θ = 0.78849 \dots + πn

sin (θ) = 2 sin (θ) cos (θ)

x, arccos (e^{- x}) = \frac{π}{3}

2 cos^{2} (4 x + 1) = 0

x, 2 sin (x) = - 1

t, f = a cos (\frac{t π}{6} - \frac{11 π}{12})

What is the general solution for solvefor θ,(90^2)/(250(32.2))=tan(θ) ?
The general solution for solvefor θ,(90^2)/(250(32.2))=tan(θ) is θ=0.78849…+pin