What is the general solution for cos^2(t)-sin^2(t)=-1 ?

The general solution for cos^2(t)-sin^2(t)=-1 is t= pi/2+pin

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cos^2(t)-sin^2(t)=-1

cos^{2} (t) - sin^{2} (t) = - 1

t = \frac{π}{2} + πn

Solution steps

cos^{2} (t) - sin^{2} (t) = - 1

Rewrite using trig identities

cos (2 t) = - 1

General solutions for

cos (2 t) = - 1

2 t = π + 2 πn

Solve

2 t = π + 2 πn : t = \frac{π}{2} + πn

t = \frac{π}{2} + πn

- a^{2} c_{1} cos (a x) - a^{2} c_{2} sin (a x) = 0

10 = - 12 sin (x) + 1.8 cos (x)

8 tan (B) + 12 = 3 tan (B) + 7

- 2 + sin (2 θ) = - \frac{3}{2}

tan (c) = \frac{24}{7}

What is the general solution for cos^2(t)-sin^2(t)=-1 ?
The general solution for cos^2(t)-sin^2(t)=-1 is t= pi/2+pin