What is the general solution for solvefor x,sin^2(x)-sin(x)-2=0 ?

The general solution for solvefor x,sin^2(x)-sin(x)-2=0 is x=(3pi)/2+2pin

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solvefor x,sin^2(x)-sin(x)-2=0

solve for

x, sin^{2} (x) - sin (x) - 2 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - sin (x) - 2 = 0

Solve by substitution

sin (x) = 2, sin (x) = - 1

sin (x) = 2 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

cos (x - \frac{2 π}{3}) = \frac{1}{2}

3 sin (θ) = 3

cos (2 θ) + sin (θ) = 0, 0 \leq θ < 2 π

cos (\frac{π}{3} x - \frac{π}{4}) = \frac{2}{2}

\frac{sin ( x )}{1} = \frac{3}{5}

What is the general solution for solvefor x,sin^2(x)-sin(x)-2=0 ?
The general solution for solvefor x,sin^2(x)-sin(x)-2=0 is x=(3pi)/2+2pin