What is the general solution for sec(2x-10)=csc(32) ?

The general solution for sec(2x-10)=csc(32) is x=180n+5+(1.01229…)/2 ,x=180+180n+5-(1.01229…)/2

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sec(2x-10)=csc(32)

sec (2 x - 1 0^{\circ}) = csc (3 2^{\circ})

x = 18 0^{\circ} n + 5^{\circ} + \frac{1.01229 \dots}{2}, x = 18 0^{\circ} + 18 0^{\circ} n + 5^{\circ} - \frac{1.01229 \dots}{2}

Solution steps

sec (2 x - 1 0^{\circ}) = csc (3 2^{\circ})

Apply trig inverse properties

2 x - 1 0^{\circ} = arcsec (csc (3 2^{\circ})) + 36 0^{\circ} n, 2 x - 1 0^{\circ} = 36 0^{\circ} - arcsec (csc (3 2^{\circ})) + 36 0^{\circ} n

Solve

2 x - 1 0^{\circ} = arcsec (csc (3 2^{\circ})) + 36 0^{\circ} n : x = 18 0^{\circ} n + 5^{\circ} + \frac{arcsec ( csc ( 3 2 ^{\circ} ) )}{2}

Solve

2 x - 1 0^{\circ} = 36 0^{\circ} - arcsec (csc (3 2^{\circ})) + 36 0^{\circ} n : x = 18 0^{\circ} + 18 0^{\circ} n + 5^{\circ} - \frac{arcsec ( csc ( 3 2 ^{\circ} ) )}{2}

x = 18 0^{\circ} n + 5^{\circ} + \frac{arcsec ( csc ( 3 2 ^{\circ} ) )}{2}, x = 18 0^{\circ} + 18 0^{\circ} n + 5^{\circ} - \frac{arcsec ( csc ( 3 2 ^{\circ} ) )}{2}

Show solutions in decimal form

x = 18 0^{\circ} n + 5^{\circ} + \frac{1.01229 \dots}{2}, x = 18 0^{\circ} + 18 0^{\circ} n + 5^{\circ} - \frac{1.01229 \dots}{2}

(5 tan (θ) + 25) = 0

4 = cos (x)

x, e^{4 y} = cos (4 x + y)

3 tan (2 x) - 3 cot (x) = 0

cos (θ) = (\frac{1}{4})

What is the general solution for sec(2x-10)=csc(32) ?
The general solution for sec(2x-10)=csc(32) is x=180n+5+(1.01229…)/2 ,x=180+180n+5-(1.01229…)/2