What is the general solution for 5sin^2(θ)-11sin(θ)+6=0 ?

The general solution for 5sin^2(θ)-11sin(θ)+6=0 is θ= pi/2+2pin

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5sin^2(θ)-11sin(θ)+6=0

5 sin^{2} (θ) - 11 sin (θ) + 6 = 0

θ = \frac{π}{2} + 2 πn

Solution steps

5 sin^{2} (θ) - 11 sin (θ) + 6 = 0

Solve by substitution

sin (θ) = \frac{6}{5}, sin (θ) = 1

sin (θ) = \frac{6}{5} :

No Solution

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn

cos (x) = \frac{11}{14}, sin (x)

sin^{2} (2 x) + cos^{2} (3 x) = 1

sin (θ) = 0.9848

cot^{(2)} (x) + 2 cot (x) + 1 = 0

cos (x) cos (x) = \frac{( 1 - sin ^{2} ( x ) )}{sin ( x )}

What is the general solution for 5sin^2(θ)-11sin(θ)+6=0 ?
The general solution for 5sin^2(θ)-11sin(θ)+6=0 is θ= pi/2+2pin