cos(b)= 12/37

Lösung

cos (b) = \frac{12}{37}

b = 1.24049 \dots + 2 πn, b = 2 π - 1.24049 \dots + 2 πn

Grad

b = 71.07535 \dots^{\circ} + 36 0^{\circ} n, b = 288.92464 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (b) = \frac{12}{37}

Wende die Eigenschaften der Trigonometrie an

cos (b) = \frac{12}{37}

Allgemeine Lösung für

cos (b) = \frac{12}{37}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

b = arccos (\frac{12}{37}) + 2 πn, b = 2 π - arccos (\frac{12}{37}) + 2 πn

b = arccos (\frac{12}{37}) + 2 πn, b = 2 π - arccos (\frac{12}{37}) + 2 πn

Zeige Lösungen in Dezimalform

b = 1.24049 \dots + 2 πn, b = 2 π - 1.24049 \dots + 2 πn

27 (sin (2 t) cos (t) - (sin (t))^{3}) = 0

2 cos^{2} (x) + cos^{2} (x) = 0

cos (t) = \frac{1}{3}

(1 - sin (x)) (\frac{( 1 + sin ( x ) )}{2 cos ( x )}) = 1

\frac{9.03}{sin ( 4 0 ^{\circ} )} = \frac{10}{sin ( x )}