What is the general solution for 2cos^2(x)+cos^2(x)=0 ?

The general solution for 2cos^2(x)+cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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2cos^2(x)+cos^2(x)=0

2 cos^{2} (x) + cos^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

2 cos^{2} (x) + cos^{2} (x) = 0

Simplify

2 cos^{2} (x) + cos^{2} (x) : 3 cos^{2} (x)

3 cos^{2} (x) = 0

Divide both sides by

3

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (t) = \frac{1}{3}

(1 - sin (x)) (\frac{( 1 + sin ( x ) )}{2 cos ( x )}) = 1

\frac{9.03}{sin ( 4 0 ^{\circ} )} = \frac{10}{sin ( x )}

tan (θ) (sec (θ) - 1) = 0

tan (x) + sec (x) = 2

What is the general solution for 2cos^2(x)+cos^2(x)=0 ?
The general solution for 2cos^2(x)+cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin