What is the general solution for sin(θ)=(-1)/(sqrt(17)) ?

The general solution for sin(θ)=(-1)/(sqrt(17)) is θ=-0.24497…+2pin,θ=pi+0.24497…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=(-1)/(sqrt(17))

sin (θ) = \frac{- 1}{17}

θ = - 0.24497 \dots + 2 πn, θ = π + 0.24497 \dots + 2 πn

Solution steps

sin (θ) = \frac{- 1}{17}

Simplify

\frac{- 1}{17} : - \frac{17}{17}

Apply trig inverse properties

θ = arcsin (- \frac{17}{17}) + 2 πn, θ = π + arcsin (\frac{17}{17}) + 2 πn

Show solutions in decimal form

θ = - 0.24497 \dots + 2 πn, θ = π + 0.24497 \dots + 2 πn

tan (x) + cot (x) = 3, = tan (3 x) + cot (3 x)

x, cos^{2} (x) = sin^{2} (x)

3 cot (x) - 1 = cot^{2} (x)

sin (x) = - 0.974

sin (x) = - 0.978

What is the general solution for sin(θ)=(-1)/(sqrt(17)) ?
The general solution for sin(θ)=(-1)/(sqrt(17)) is θ=-0.24497…+2pin,θ=pi+0.24497…+2pin