What is the general solution for sin(0)=-sin(o)cos(0) ?

The general solution for sin(0)=-sin(o)cos(0) is o=2pin,o=pi+2pin

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sin(0)=-sin(o)cos(0)

sin (0) = - sin (o) cos (0)

o = 2 πn, o = π + 2 πn

Solution steps

sin (0) = - sin (o) cos (0)

sin (0) = 0

cos (0) = 1

0 = - sin (o) \cdot 1

Switch sides

- sin (o) \cdot 1 = 0

Divide both sides by

- 1

sin (o) = 0

General solutions for

sin (o) = 0

o = 0 + 2 πn, o = π + 2 πn

Solve

o = 0 + 2 πn : o = 2 πn

o = 2 πn, o = π + 2 πn

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sin (x) = 32

88.2 sin (x) - 12.78 = 0.1 \cdot 88.2 cos (x)

1 + sin (x) = 2 \cdot cos (x)

sin (x) = 0.75 cos (x)

What is the general solution for sin(0)=-sin(o)cos(0) ?
The general solution for sin(0)=-sin(o)cos(0) is o=2pin,o=pi+2pin