What is the general solution for sin(0)=-sin(o)cos(0) ?

The general solution for sin(0)=-sin(o)cos(0) is o=2pin,o=pi+2pin

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sin(0)=-sin(o)cos(0)

sin (0) = - sin (o) cos (0)

o = 2 πn, o = π + 2 πn

Degrees

o = 0^{\circ} + 36 0^{\circ} n, o = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (0) = - sin (o) cos (0)

sin (0) = 0

sin (0)

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

cos (0) = 1

cos (0)

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= 1

0 = - sin (o) \cdot 1

Switch sides

- sin (o) \cdot 1 = 0

Divide both sides by

- 1

- sin (o) \cdot 1 = 0

Divide both sides by

- 1

\frac{- sin ( o ) \cdot 1}{- 1} = \frac{0}{- 1}

Simplify

sin (o) = 0

sin (o) = 0

General solutions for

sin (o) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

o = 0 + 2 πn, o = π + 2 πn

o = 0 + 2 πn, o = π + 2 πn

Solve

o = 0 + 2 πn : o = 2 πn

o = 0 + 2 πn

0 + 2 πn = 2 πn

o = 2 πn

o = 2 πn, o = π + 2 πn

What is the general solution for sin(0)=-sin(o)cos(0) ?
The general solution for sin(0)=-sin(o)cos(0) is o=2pin,o=pi+2pin