What is the general solution for (sec(x)+csc(x))/(1+tan(x))=sin(x) ?

The general solution for (sec(x)+csc(x))/(1+tan(x))=sin(x) is No Solution for x\in\mathbb{R}

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Popular Trigonometry >

(sec(x)+csc(x))/(1+tan(x))=sin(x)

Solution

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} = sin (x)

Solution

No Solution for x \in R

Solution steps

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} = sin (x)

Subtract

sin (x)

from both sides

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} - sin (x) = 0

Simplify

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} - sin (x) : \frac{sec ( x ) + csc ( x ) - sin ( x ) ( 1 + tan ( x ) )}{1 + tan ( x )}

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} - sin (x)

Convert element to fraction:

sin (x) = \frac{sin ( x ) ( 1 + tan ( x ) )}{1 + tan ( x )}

= \frac{sec ( x ) + csc ( x )}{1 + tan ( x )} - \frac{sin ( x ) ( 1 + tan ( x ) )}{1 + tan ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sec ( x ) + csc ( x ) - sin ( x ) ( 1 + tan ( x ) )}{1 + tan ( x )}

\frac{sec ( x ) + csc ( x ) - sin ( x ) ( 1 + tan ( x ) )}{1 + tan ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sec (x) + csc (x) - sin (x) (1 + tan (x)) = 0

Express with sin, cos

csc (x) + sec (x) - (1 + tan (x)) sin (x)

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

= \frac{1}{sin ( x )} + sec (x) - (1 + tan (x)) sin (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{1}{sin ( x )} + \frac{1}{cos ( x )} - (1 + tan (x)) sin (x)

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{1}{sin ( x )} + \frac{1}{cos ( x )} - (1 + \frac{sin ( x )}{cos ( x )}) sin (x)

Simplify

\frac{1}{sin ( x )} + \frac{1}{cos ( x )} - (1 + \frac{sin ( x )}{cos ( x )}) sin (x) : \frac{cos ( x ) + sin ( x ) - sin ^{2} ( x ) ( cos ( x ) + sin ( x ) )}{sin ( x ) cos ( x )}

\frac{1}{sin ( x )} + \frac{1}{cos ( x )} - (1 + \frac{sin ( x )}{cos ( x )}) sin (x)

Join

1 + \frac{sin ( x )}{cos ( x )} : \frac{cos ( x ) + sin ( x )}{cos ( x )}

1 + \frac{sin ( x )}{cos ( x )}

Convert element to fraction:

1 = \frac{1 cos ( x )}{cos ( x )}

= \frac{1 \cdot cos ( x )}{cos ( x )} + \frac{sin ( x )}{cos ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot cos ( x ) + sin ( x )}{cos ( x )}

Multiply:

1 \cdot cos (x) = cos (x)

= \frac{cos ( x ) + sin ( x )}{cos ( x )}

= \frac{1}{sin ( x )} + \frac{1}{cos ( x )} - \frac{cos ( x ) + sin ( x )}{cos ( x )} sin (x)

Multiply

\frac{cos ( x ) + sin ( x )}{cos ( x )} sin (x) : \frac{sin ( x ) ( cos ( x ) + sin ( x ) )}{cos ( x )}

\frac{cos ( x ) + sin ( x )}{cos ( x )} sin (x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( cos ( x ) + sin ( x ) ) sin ( x )}{cos ( x )}

= \frac{1}{sin ( x )} + \frac{1}{cos ( x )} - \frac{( cos ( x ) + sin ( x ) ) sin ( x )}{cos ( x )}

Least Common Multiplier of

sin (x), cos (x), cos (x) : sin (x) cos (x)

sin (x), cos (x), cos (x)

Lowest Common Multiplier (LCM)

Compute an expression comprised of factors that appear in at least one of the factored expressions

= sin (x) cos (x)

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

sin (x) cos (x)

For

\frac{1}{sin ( x )} :

multiply the denominator and numerator by

cos (x)

\frac{1}{sin ( x )} = \frac{1 \cdot cos ( x )}{sin ( x ) cos ( x )} = \frac{cos ( x )}{sin ( x ) cos ( x )}

For

\frac{1}{cos ( x )} :

multiply the denominator and numerator by

sin (x)

\frac{1}{cos ( x )} = \frac{1 \cdot sin ( x )}{cos ( x ) sin ( x )} = \frac{sin ( x )}{sin ( x ) cos ( x )}

For

\frac{( cos ( x ) + sin ( x ) ) sin ( x )}{cos ( x )} :

multiply the denominator and numerator by

sin (x)

\frac{( cos ( x ) + sin ( x ) ) sin ( x )}{cos ( x )} = \frac{( cos ( x ) + sin ( x ) ) sin ( x ) sin ( x )}{cos ( x ) sin ( x )} = \frac{sin ^{2} ( x ) ( cos ( x ) + sin ( x ) )}{sin ( x ) cos ( x )}

= \frac{cos ( x )}{sin ( x ) cos ( x )} + \frac{sin ( x )}{sin ( x ) cos ( x )} - \frac{sin ^{2} ( x ) ( cos ( x ) + sin ( x ) )}{sin ( x ) cos ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ( x ) + sin ( x ) - sin ^{2} ( x ) ( cos ( x ) + sin ( x ) )}{sin ( x ) cos ( x )}

= \frac{cos ( x ) + sin ( x ) - sin ^{2} ( x ) ( cos ( x ) + sin ( x ) )}{sin ( x ) cos ( x )}

\frac{cos ( x ) + sin ( x ) - ( cos ( x ) + sin ( x ) ) sin ^{2} ( x )}{cos ( x ) sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (x) + sin (x) - (cos (x) + sin (x)) sin^{2} (x) = 0

Factor

cos (x) + sin (x) - (cos (x) + sin (x)) sin^{2} (x) : - (cos (x) + sin (x)) (sin (x) + 1) (sin (x) - 1)

cos (x) + sin (x) - (cos (x) + sin (x)) sin^{2} (x)

Rewrite as

= - (cos (x) + sin (x)) sin^{2} (x) + 1 \cdot (cos (x) + sin (x))

Factor out common term

(cos (x) + sin (x))

= (cos (x) + sin (x)) (- sin^{2} (x) + 1)

Factor

- sin^{2} (x) + 1 : - (sin (x) + 1) (sin (x) - 1)

- sin^{2} (x) + 1

Factor out common term

- 1

= - (sin^{2} (x) - 1)

Factor

sin^{2} (x) - 1 : (sin (x) + 1) (sin (x) - 1)

sin^{2} (x) - 1

Rewrite

1

1^{2}

= sin^{2} (x) - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

sin^{2} (x) - 1^{2} = (sin (x) + 1) (sin (x) - 1)

= (sin (x) + 1) (sin (x) - 1)

= - (sin (x) + 1) (sin (x) - 1)

= (cos (x) + sin (x)) (- (sin (x) + 1) (sin (x) - 1))

Refine

= - (sin (x) + 1) (sin (x) - 1) (cos (x) + sin (x))

- (cos (x) + sin (x)) (sin (x) + 1) (sin (x) - 1) = 0

Solving each part separately

cos (x) + sin (x) = 0 or sin (x) + 1 = 0 or sin (x) - 1 = 0

cos (x) + sin (x) = 0 : x = \frac{3 π}{4} + πn

cos (x) + sin (x) = 0

Rewrite using trig identities

cos (x) + sin (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{cos ( x ) + sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

1 + \frac{sin ( x )}{cos ( x )} = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 + tan (x) = 0

1 + tan (x) = 0

Move

1

to the right side

1 + tan (x) = 0

Subtract

1

from both sides

1 + tan (x) - 1 = 0 - 1

Simplify

tan (x) = - 1

tan (x) = - 1

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

sin (x) + 1 = 0 : x = \frac{3 π}{2} + 2 πn

sin (x) + 1 = 0

Move

1

to the right side

sin (x) + 1 = 0

Subtract

1

from both sides

sin (x) + 1 - 1 = 0 - 1

Simplify

sin (x) = - 1

sin (x) = - 1

General solutions for

sin (x) = - 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{3 π}{2} + 2 πn

x = \frac{3 π}{2} + 2 πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

sin (x) - 1 = 0

Move

1

to the right side

sin (x) - 1 = 0

Add

1

to both sides

sin (x) - 1 + 1 = 0 + 1

Simplify

sin (x) = 1

sin (x) = 1

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{4} + πn, x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{3 π}{4} + πn, \frac{3 π}{2} + 2 πn, \frac{π}{2} + 2 πn

No Solution for x \in R

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for (sec(x)+csc(x))/(1+tan(x))=sin(x) ?
The general solution for (sec(x)+csc(x))/(1+tan(x))=sin(x) is No Solution for x\in\mathbb{R}