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Popular Trigonometry >

4tan(x)+cot(x)=5

  • Pre Algebra
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Solution

4tan(x)+cot(x)=5

Solution

x=0.24497…+πn,x=4π​+πn
+1
Degrees
x=14.03624…∘+180∘n,x=45∘+180∘n
Solution steps
4tan(x)+cot(x)=5
Subtract 5 from both sides4tan(x)+cot(x)−5=0
Rewrite using trig identities
−5+cot(x)+4tan(x)
Use the basic trigonometric identity: tan(x)=cot(x)1​=−5+cot(x)+4⋅cot(x)1​
4⋅cot(x)1​=cot(x)4​
4⋅cot(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=cot(x)1⋅4​
Multiply the numbers: 1⋅4=4=cot(x)4​
=−5+cot(x)+cot(x)4​
−5+cot(x)+cot(x)4​=0
Solve by substitution
−5+cot(x)+cot(x)4​=0
Let: cot(x)=u−5+u+u4​=0
−5+u+u4​=0:u=4,u=1
−5+u+u4​=0
Multiply both sides by u
−5+u+u4​=0
Multiply both sides by u−5u+uu+u4​u=0⋅u
Simplify
−5u+uu+u4​u=0⋅u
Simplify uu:u2
uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=u1+1
Add the numbers: 1+1=2=u2
Simplify u4​u:4
u4​u
Multiply fractions: a⋅cb​=ca⋅b​=u4u​
Cancel the common factor: u=4
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
−5u+u2+4=0
−5u+u2+4=0
−5u+u2+4=0
Solve −5u+u2+4=0:u=4,u=1
−5u+u2+4=0
Write in the standard form ax2+bx+c=0u2−5u+4=0
Solve with the quadratic formula
u2−5u+4=0
Quadratic Equation Formula:
For a=1,b=−5,c=4u1,2​=2⋅1−(−5)±(−5)2−4⋅1⋅4​​
u1,2​=2⋅1−(−5)±(−5)2−4⋅1⋅4​​
(−5)2−4⋅1⋅4​=3
(−5)2−4⋅1⋅4​
Apply exponent rule: (−a)n=an,if n is even(−5)2=52=52−4⋅1⋅4​
Multiply the numbers: 4⋅1⋅4=16=52−16​
52=25=25−16​
Subtract the numbers: 25−16=9=9​
Factor the number: 9=32=32​
Apply radical rule: 32​=3=3
u1,2​=2⋅1−(−5)±3​
Separate the solutionsu1​=2⋅1−(−5)+3​,u2​=2⋅1−(−5)−3​
u=2⋅1−(−5)+3​:4
2⋅1−(−5)+3​
Apply rule −(−a)=a=2⋅15+3​
Add the numbers: 5+3=8=2⋅18​
Multiply the numbers: 2⋅1=2=28​
Divide the numbers: 28​=4=4
u=2⋅1−(−5)−3​:1
2⋅1−(−5)−3​
Apply rule −(−a)=a=2⋅15−3​
Subtract the numbers: 5−3=2=2⋅12​
Multiply the numbers: 2⋅1=2=22​
Apply rule aa​=1=1
The solutions to the quadratic equation are:u=4,u=1
u=4,u=1
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of −5+u+u4​ and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=4,u=1
Substitute back u=cot(x)cot(x)=4,cot(x)=1
cot(x)=4,cot(x)=1
cot(x)=4:x=arccot(4)+πn
cot(x)=4
Apply trig inverse properties
cot(x)=4
General solutions for cot(x)=4cot(x)=a⇒x=arccot(a)+πnx=arccot(4)+πn
x=arccot(4)+πn
cot(x)=1:x=4π​+πn
cot(x)=1
General solutions for cot(x)=1
cot(x) periodicity table with πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cot(x)∓∞3​133​​0−33​​−1−3​​​
x=4π​+πn
x=4π​+πn
Combine all the solutionsx=arccot(4)+πn,x=4π​+πn
Show solutions in decimal formx=0.24497…+πn,x=4π​+πn

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Popular Examples

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Frequently Asked Questions (FAQ)

  • What is the general solution for 4tan(x)+cot(x)=5 ?

    The general solution for 4tan(x)+cot(x)=5 is x=0.24497…+pin,x= pi/4+pin
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