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Popular Trigonometry >

20=27sin(x)-1.5cos(x)

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Solution

20=27sin(x)−1.5cos(x)

Solution

x=2.36461…+2πn,x=0.88797…+2πn
+1
Degrees
x=135.48245…∘+360∘n,x=50.87720…∘+360∘n
Solution steps
20=27sin(x)−1.5cos(x)
Add 1.5cos(x) to both sides27sin(x)=20+1.5cos(x)
Square both sides(27sin(x))2=(20+1.5cos(x))2
Subtract (20+1.5cos(x))2 from both sides729sin2(x)−400−60cos(x)−2.25cos2(x)=0
Rewrite using trig identities
−400−2.25cos2(x)−60cos(x)+729sin2(x)
Use the Pythagorean identity: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−400−2.25cos2(x)−60cos(x)+729(1−cos2(x))
Simplify −400−2.25cos2(x)−60cos(x)+729(1−cos2(x)):−731.25cos2(x)−60cos(x)+329
−400−2.25cos2(x)−60cos(x)+729(1−cos2(x))
Expand 729(1−cos2(x)):729−729cos2(x)
729(1−cos2(x))
Apply the distributive law: a(b−c)=ab−aca=729,b=1,c=cos2(x)=729⋅1−729cos2(x)
Multiply the numbers: 729⋅1=729=729−729cos2(x)
=−400−2.25cos2(x)−60cos(x)+729−729cos2(x)
Simplify −400−2.25cos2(x)−60cos(x)+729−729cos2(x):−731.25cos2(x)−60cos(x)+329
−400−2.25cos2(x)−60cos(x)+729−729cos2(x)
Group like terms=−2.25cos2(x)−60cos(x)−729cos2(x)−400+729
Add similar elements: −2.25cos2(x)−729cos2(x)=−731.25cos2(x)=−731.25cos2(x)−60cos(x)−400+729
Add/Subtract the numbers: −400+729=329=−731.25cos2(x)−60cos(x)+329
=−731.25cos2(x)−60cos(x)+329
=−731.25cos2(x)−60cos(x)+329
329−60cos(x)−731.25cos2(x)=0
Solve by substitution
329−60cos(x)−731.25cos2(x)=0
Let: cos(x)=u329−60u−731.25u2=0
329−60u−731.25u2=0:u=−1462506000+9659250000​​,u=1462509659250000​−6000​
329−60u−731.25u2=0
Multiply both sides by 100
329−60u−731.25u2=0
To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere are 2digits to the right of the decimal point, therefore multiply by 100329⋅100−60u⋅100−731.25u2⋅100=0⋅100
Refine32900−6000u−73125u2=0
32900−6000u−73125u2=0
Write in the standard form ax2+bx+c=0−73125u2−6000u+32900=0
Solve with the quadratic formula
−73125u2−6000u+32900=0
Quadratic Equation Formula:
For a=−73125,b=−6000,c=32900u1,2​=2(−73125)−(−6000)±(−6000)2−4(−73125)⋅32900​​
u1,2​=2(−73125)−(−6000)±(−6000)2−4(−73125)⋅32900​​
(−6000)2−4(−73125)⋅32900​=9659250000​
(−6000)2−4(−73125)⋅32900​
Apply rule −(−a)=a=(−6000)2+4⋅73125⋅32900​
Apply exponent rule: (−a)n=an,if n is even(−6000)2=60002=60002+4⋅73125⋅32900​
Multiply the numbers: 4⋅73125⋅32900=9623250000=60002+9623250000​
60002=36000000=36000000+9623250000​
Add the numbers: 36000000+9623250000=9659250000=9659250000​
u1,2​=2(−73125)−(−6000)±9659250000​​
Separate the solutionsu1​=2(−73125)−(−6000)+9659250000​​,u2​=2(−73125)−(−6000)−9659250000​​
u=2(−73125)−(−6000)+9659250000​​:−1462506000+9659250000​​
2(−73125)−(−6000)+9659250000​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅731256000+9659250000​​
Multiply the numbers: 2⋅73125=146250=−1462506000+9659250000​​
Apply the fraction rule: −ba​=−ba​=−1462506000+9659250000​​
u=2(−73125)−(−6000)−9659250000​​:1462509659250000​−6000​
2(−73125)−(−6000)−9659250000​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅731256000−9659250000​​
Multiply the numbers: 2⋅73125=146250=−1462506000−9659250000​​
Apply the fraction rule: −b−a​=ba​6000−9659250000​=−(9659250000​−6000)=1462509659250000​−6000​
The solutions to the quadratic equation are:u=−1462506000+9659250000​​,u=1462509659250000​−6000​
Substitute back u=cos(x)cos(x)=−1462506000+9659250000​​,cos(x)=1462509659250000​−6000​
cos(x)=−1462506000+9659250000​​,cos(x)=1462509659250000​−6000​
cos(x)=−1462506000+9659250000​​:x=arccos(−1462506000+9659250000​​)+2πn,x=−arccos(−1462506000+9659250000​​)+2πn
cos(x)=−1462506000+9659250000​​
Apply trig inverse properties
cos(x)=−1462506000+9659250000​​
General solutions for cos(x)=−1462506000+9659250000​​cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnx=arccos(−1462506000+9659250000​​)+2πn,x=−arccos(−1462506000+9659250000​​)+2πn
x=arccos(−1462506000+9659250000​​)+2πn,x=−arccos(−1462506000+9659250000​​)+2πn
cos(x)=1462509659250000​−6000​:x=arccos(1462509659250000​−6000​)+2πn,x=2π−arccos(1462509659250000​−6000​)+2πn
cos(x)=1462509659250000​−6000​
Apply trig inverse properties
cos(x)=1462509659250000​−6000​
General solutions for cos(x)=1462509659250000​−6000​cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnx=arccos(1462509659250000​−6000​)+2πn,x=2π−arccos(1462509659250000​−6000​)+2πn
x=arccos(1462509659250000​−6000​)+2πn,x=2π−arccos(1462509659250000​−6000​)+2πn
Combine all the solutionsx=arccos(−1462506000+9659250000​​)+2πn,x=−arccos(−1462506000+9659250000​​)+2πn,x=arccos(1462509659250000​−6000​)+2πn,x=2π−arccos(1462509659250000​−6000​)+2πn
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into 27sin(x)−1.5cos(x)=20
Remove the ones that don't agree with the equation.
Check the solution arccos(−1462506000+9659250000​​)+2πn:True
arccos(−1462506000+9659250000​​)+2πn
Plug in n=1arccos(−1462506000+9659250000​​)+2π1
For 27sin(x)−1.5cos(x)=20plug inx=arccos(−1462506000+9659250000​​)+2π127sin(arccos(−1462506000+9659250000​​)+2π1)−1.5cos(arccos(−1462506000+9659250000​​)+2π1)=20
Refine20=20
⇒True
Check the solution −arccos(−1462506000+9659250000​​)+2πn:False
−arccos(−1462506000+9659250000​​)+2πn
Plug in n=1−arccos(−1462506000+9659250000​​)+2π1
For 27sin(x)−1.5cos(x)=20plug inx=−arccos(−1462506000+9659250000​​)+2π127sin(−arccos(−1462506000+9659250000​​)+2π1)−1.5cos(−arccos(−1462506000+9659250000​​)+2π1)=20
Refine−17.86089…=20
⇒False
Check the solution arccos(1462509659250000​−6000​)+2πn:True
arccos(1462509659250000​−6000​)+2πn
Plug in n=1arccos(1462509659250000​−6000​)+2π1
For 27sin(x)−1.5cos(x)=20plug inx=arccos(1462509659250000​−6000​)+2π127sin(arccos(1462509659250000​−6000​)+2π1)−1.5cos(arccos(1462509659250000​−6000​)+2π1)=20
Refine20=20
⇒True
Check the solution 2π−arccos(1462509659250000​−6000​)+2πn:False
2π−arccos(1462509659250000​−6000​)+2πn
Plug in n=12π−arccos(1462509659250000​−6000​)+2π1
For 27sin(x)−1.5cos(x)=20plug inx=2π−arccos(1462509659250000​−6000​)+2π127sin(2π−arccos(1462509659250000​−6000​)+2π1)−1.5cos(2π−arccos(1462509659250000​−6000​)+2π1)=20
Refine−21.89295…=20
⇒False
x=arccos(−1462506000+9659250000​​)+2πn,x=arccos(1462509659250000​−6000​)+2πn
Show solutions in decimal formx=2.36461…+2πn,x=0.88797…+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for 20=27sin(x)-1.5cos(x) ?

    The general solution for 20=27sin(x)-1.5cos(x) is x=2.36461…+2pin,x=0.88797…+2pin
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