What is the general solution for cos(θ)= 1/9 ?

The general solution for cos(θ)= 1/9 is θ=1.45945…+2pin,θ=2pi-1.45945…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

cos(θ)= 1/9

cos (θ) = \frac{1}{9}

θ = 1.45945 \dots + 2 πn, θ = 2 π - 1.45945 \dots + 2 πn

Degrees

θ = 83.62062 \dots^{\circ} + 36 0^{\circ} n, θ = 276.37937 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{1}{9}

Apply trig inverse properties

cos (θ) = \frac{1}{9}

General solutions for

cos (θ) = \frac{1}{9}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{1}{9}) + 2 πn, θ = 2 π - arccos (\frac{1}{9}) + 2 πn

θ = arccos (\frac{1}{9}) + 2 πn, θ = 2 π - arccos (\frac{1}{9}) + 2 πn

Show solutions in decimal form

θ = 1.45945 \dots + 2 πn, θ = 2 π - 1.45945 \dots + 2 πn

What is the general solution for cos(θ)= 1/9 ?
The general solution for cos(θ)= 1/9 is θ=1.45945…+2pin,θ=2pi-1.45945…+2pin