What is the general solution for cos(θ)= 1/9 ?

The general solution for cos(θ)= 1/9 is θ=1.45945…+2pin,θ=2pi-1.45945…+2pin

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cos(θ)= 1/9

cos (θ) = \frac{1}{9}

θ = 1.45945 \dots + 2 πn, θ = 2 π - 1.45945 \dots + 2 πn

Degrees

θ = 83.62062 \dots^{\circ} + 36 0^{\circ} n, θ = 276.37937 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{1}{9}

Apply trig inverse properties

cos (θ) = \frac{1}{9}

General solutions for

cos (θ) = \frac{1}{9}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{1}{9}) + 2 πn, θ = 2 π - arccos (\frac{1}{9}) + 2 πn

θ = arccos (\frac{1}{9}) + 2 πn, θ = 2 π - arccos (\frac{1}{9}) + 2 πn

Show solutions in decimal form

θ = 1.45945 \dots + 2 πn, θ = 2 π - 1.45945 \dots + 2 πn

- 33 sin (v) + 3 cos (v) = 32

x, - arctan (y) = arctan (x)

cot (x) = tan^{2} (x)

sin (x + b) = cos (x)

3 sin (ϕ) - cos (2 ϕ) = 1

What is the general solution for cos(θ)= 1/9 ?
The general solution for cos(θ)= 1/9 is θ=1.45945…+2pin,θ=2pi-1.45945…+2pin