What is the general solution for cos(t)= 40/41 ?

The general solution for cos(t)= 40/41 is t=0.22131…+2pin,t=2pi-0.22131…+2pin

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cos(t)= 40/41

cos (t) = \frac{40}{41}

t = 0.22131 \dots + 2 πn, t = 2 π - 0.22131 \dots + 2 πn

Degrees

t = 12.68038 \dots^{\circ} + 36 0^{\circ} n, t = 347.31961 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (t) = \frac{40}{41}

Apply trig inverse properties

cos (t) = \frac{40}{41}

General solutions for

cos (t) = \frac{40}{41}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

t = arccos (\frac{40}{41}) + 2 πn, t = 2 π - arccos (\frac{40}{41}) + 2 πn

t = arccos (\frac{40}{41}) + 2 πn, t = 2 π - arccos (\frac{40}{41}) + 2 πn

Show solutions in decimal form

t = 0.22131 \dots + 2 πn, t = 2 π - 0.22131 \dots + 2 πn

5 tan (x) = 12

cos^{2} (a) + cos (a) = 0

5 tan (x) = - 5

- 2 cos (θ - 1) = 0.5

cos (θ) = \frac{1}{9}

What is the general solution for cos(t)= 40/41 ?
The general solution for cos(t)= 40/41 is t=0.22131…+2pin,t=2pi-0.22131…+2pin