What is the general solution for arcsin(x)=-1 ?

The general solution for arcsin(x)=-1 is x=-sin(1)

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arcsin(x)=-1

arcsin (x) = - 1

x = - sin (1)

Solution steps

arcsin (x) = - 1

Apply trig inverse properties

arcsin (x) = - 1

arcsin (x) = a \Rightarrow x = sin (a)

x = sin (- 1)

sin (- 1) = - sin (1)

sin (- 1)

Use the following property:

sin (- x) = - sin (x)

sin (- 1) = - sin (1)

= - sin (1)

x = - sin (1)

x = - sin (1)

2 cos^{2} (x) + sin^{2} (x) = 1

3 \cdot tan^{2} (x) = 1

2 \cdot 3 sin (v) + 2 cos (v) = 22

2 csc^{3} (x) + 21 csc^{2} (x) + 55 csc (x) + 42 = 0

cos^{2} (\frac{x}{3}) - sin^{2} (\frac{x}{3}) = - \frac{1}{2}

What is the general solution for arcsin(x)=-1 ?
The general solution for arcsin(x)=-1 is x=-sin(1)