What is the general solution for cos(θ)=-7/15 ,cos(θ/2),180<θ<270 ?

The general solution for cos(θ)=-7/15 ,cos(θ/2),180<θ<270 is No Solution for θ\in\mathbb{R}

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cos(θ)=-7/15 ,cos(θ/2),180<θ<270

cos (θ) = - \frac{7}{15}, cos (\frac{θ}{2}), 18 0^{\circ} < θ < 27 0^{\circ}

No Solution for θ \in R

Solution steps

cos (θ) = - \frac{7}{15}, cos (\frac{θ}{2}), 18 0^{\circ} < θ < 27 0^{\circ}

Apply trig inverse properties

cos (θ) = - \frac{7}{15}

General solutions for

cos (θ) = - \frac{7}{15}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{7}{15}) + 2 πn, θ = - arccos (- \frac{7}{15}) + 2 πn

θ = arccos (- \frac{7}{15}) + 2 πn, θ = - arccos (- \frac{7}{15}) + 2 πn

Solutions for the range

cos (\frac{θ}{2})

No Solution for θ \in R

tan (x) + 2 = 0

2 6^{2} = 1 3^{2} + 1 9^{2} - (13) (19) cos (J)

4 = sec^{2} (x)

tan (\frac{x}{2}) = 4

sec (x) sin (x) + sec (x) = 2 sec (x)

What is the general solution for cos(θ)=-7/15 ,cos(θ/2),180<θ<270 ?
The general solution for cos(θ)=-7/15 ,cos(θ/2),180<θ<270 is No Solution for θ\in\mathbb{R}