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Popular Trigonometry >

5sec^3(x)-20sec(x)=0

  • Pre Algebra
  • Algebra
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Solution

5sec3(x)−20sec(x)=0

Solution

x=32π​+2πn,x=34π​+2πn,x=3π​+2πn,x=35π​+2πn
+1
Degrees
x=120∘+360∘n,x=240∘+360∘n,x=60∘+360∘n,x=300∘+360∘n
Solution steps
5sec3(x)−20sec(x)=0
Solve by substitution
5sec3(x)−20sec(x)=0
Let: sec(x)=u5u3−20u=0
5u3−20u=0:u=0,u=−2,u=2
5u3−20u=0
Factor 5u3−20u:5u(u+2)(u−2)
5u3−20u
Factor out common term 5u:5u(u2−4)
5u3−20u
Apply exponent rule: ab+c=abacu3=u2u=5u2u−20u
Rewrite 20 as 5⋅4=5u2u−5⋅4u
Factor out common term 5u=5u(u2−4)
=5u(u2−4)
Factor u2−4:(u+2)(u−2)
u2−4
Rewrite 4 as 22=u2−22
Apply Difference of Two Squares Formula: x2−y2=(x+y)(x−y)u2−22=(u+2)(u−2)=(u+2)(u−2)
=5u(u+2)(u−2)
5u(u+2)(u−2)=0
Using the Zero Factor Principle: If ab=0then a=0or b=0u=0oru+2=0oru−2=0
Solve u+2=0:u=−2
u+2=0
Move 2to the right side
u+2=0
Subtract 2 from both sidesu+2−2=0−2
Simplifyu=−2
u=−2
Solve u−2=0:u=2
u−2=0
Move 2to the right side
u−2=0
Add 2 to both sidesu−2+2=0+2
Simplifyu=2
u=2
The solutions areu=0,u=−2,u=2
Substitute back u=sec(x)sec(x)=0,sec(x)=−2,sec(x)=2
sec(x)=0,sec(x)=−2,sec(x)=2
sec(x)=0:No Solution
sec(x)=0
sec(x)≤−1orsec(x)≥1NoSolution
sec(x)=−2:x=32π​+2πn,x=34π​+2πn
sec(x)=−2
General solutions for sec(x)=−2
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
x=32π​+2πn,x=34π​+2πn
x=32π​+2πn,x=34π​+2πn
sec(x)=2:x=3π​+2πn,x=35π​+2πn
sec(x)=2
General solutions for sec(x)=2
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
x=3π​+2πn,x=35π​+2πn
x=3π​+2πn,x=35π​+2πn
Combine all the solutionsx=32π​+2πn,x=34π​+2πn,x=3π​+2πn,x=35π​+2πn

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