What is the general solution for sin(A)=((60)sin(155))/(97.73) ?

The general solution for sin(A)=((60)sin(155))/(97.73) is A=0.26246…+360n,A=180-0.26246…+360n

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sin(A)=((60)sin(155))/(97.73)

sin (A) = \frac{( 60 ) sin ( 15 5 ^{\circ} )}{97.73}

A = 0.26246 \dots + 36 0^{\circ} n, A = 18 0^{\circ} - 0.26246 \dots + 36 0^{\circ} n

Radians

A = 0.26246 \dots + 2 πn, A = π - 0.26246 \dots + 2 πn

Solution steps

sin (A) = \frac{( 60 ) sin ( 15 5 ^{\circ} )}{97.73}

Apply trig inverse properties

sin (A) = \frac{60 sin ( 15 5 ^{\circ} )}{97.73}

General solutions for

sin (A) = \frac{60 sin ( 15 5 ^{\circ} )}{97.73}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

A = arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.73}) + 36 0^{\circ} n, A = 18 0^{\circ} - arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.73}) + 36 0^{\circ} n

A = arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.73}) + 36 0^{\circ} n, A = 18 0^{\circ} - arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.73}) + 36 0^{\circ} n

Show solutions in decimal form

A = 0.26246 \dots + 36 0^{\circ} n, A = 18 0^{\circ} - 0.26246 \dots + 36 0^{\circ} n

cos (θ) = 1 - cos (θ)

tan (θ) = - 1.5

tan (θ) = \frac{30}{20}

10 cos (θ) - 53 = 0

tan (θ) = \frac{8}{- 6}

What is the general solution for sin(A)=((60)sin(155))/(97.73) ?
The general solution for sin(A)=((60)sin(155))/(97.73) is A=0.26246…+360n,A=180-0.26246…+360n