What is the general solution for -2+cot(θ)=-3,0<= θ<2pi ?

The general solution for -2+cot(θ)=-3,0<= θ<2pi is θ=(3pi)/4 ,θ=(7pi)/4

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-2+cot(θ)=-3,0<= θ<2pi

- 2 + cot (θ) = - 3, 0 \leq θ < 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

Degrees

θ = 13 5^{\circ}, θ = 31 5^{\circ}

Solution steps

- 2 + cot (θ) = - 3, 0 \leq θ < 2 π

Move

2

to the right side

- 2 + cot (θ) = - 3

Add

2

to both sides

- 2 + cot (θ) + 2 = - 3 + 2

Simplify

cot (θ) = - 1

cot (θ) = - 1

General solutions for

cot (θ) = - 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

sec (θ) csc (θ) = 2 csc (θ)

sin (A) = \frac{( 60 ) sin ( 15 5 ^{\circ} )}{97.73}

cos (θ) = 1 - cos (θ)

tan (θ) = - 1.5

tan (θ) = \frac{30}{20}

What is the general solution for -2+cot(θ)=-3,0<= θ<2pi ?
The general solution for -2+cot(θ)=-3,0<= θ<2pi is θ=(3pi)/4 ,θ=(7pi)/4