What is the general solution for cos(x)tan(x)-cos(x)=0,0<= x<= 2pi ?

The general solution for cos(x)tan(x)-cos(x)=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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cos(x)tan(x)-cos(x)=0,0<= x<= 2pi

cos (x) tan (x) - cos (x) = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}

Solution steps

cos (x) tan (x) - cos (x) = 0, 0 \leq x \leq 2 π

Factor

cos (x) tan (x) - cos (x) : cos (x) (tan (x) - 1)

cos (x) tan (x) - cos (x)

Factor out common term

cos (x)

= cos (x) (tan (x) - 1)

cos (x) (tan (x) - 1) = 0

Solving each part separately

cos (x) = 0 or tan (x) - 1 = 0

cos (x) = 0, 0 \leq x \leq 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

cos (x) = 0, 0 \leq x \leq 2 π

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{2}, x = \frac{3 π}{2}

tan (x) - 1 = 0, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{5 π}{4}

tan (x) - 1 = 0, 0 \leq x \leq 2 π

Move

1

to the right side

tan (x) - 1 = 0

Add

1

to both sides

tan (x) - 1 + 1 = 0 + 1

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Combine all the solutions

x = \frac{π}{2}, x = \frac{3 π}{2}, x = \frac{π}{4}, x = \frac{5 π}{4}

Since the equation is undefined for:

\frac{π}{2}, \frac{3 π}{2}

x = \frac{π}{4}, x = \frac{5 π}{4}

sin^{2} (2 θ) - 5 sin (2 θ) - 1 = 0

- \frac{π}{30} sin (\frac{π}{90} (x + 20)) = 0

sin (2 x) = - \frac{1}{2}

cos (x) = - \frac{22}{7.28 \cdot 20}

sec^{2} (x) = 4 tan (x)

What is the general solution for cos(x)tan(x)-cos(x)=0,0<= x<= 2pi ?
The general solution for cos(x)tan(x)-cos(x)=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4