What is the general solution for cos(θ)=-sqrt(2/5) ?

The general solution for cos(θ)=-sqrt(2/5) is θ=2.25551…+2pin,θ=-2.25551…+2pin

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cos(θ)=-sqrt(2/5)

cos (θ) = - \frac{2}{5}

θ = 2.25551 \dots + 2 πn, θ = - 2.25551 \dots + 2 πn

Degrees

θ = 129.23152 \dots^{\circ} + 36 0^{\circ} n, θ = - 129.23152 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{2}{5}

Apply trig inverse properties

cos (θ) = - \frac{2}{5}

General solutions for

cos (θ) = - \frac{2}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{2}{5}) + 2 πn, θ = - arccos (- \frac{2}{5}) + 2 πn

θ = arccos (- \frac{2}{5}) + 2 πn, θ = - arccos (- \frac{2}{5}) + 2 πn

Show solutions in decimal form

θ = 2.25551 \dots + 2 πn, θ = - 2.25551 \dots + 2 πn

tan (x) = \frac{1}{sin ( 2 x )}, 0 \leq x \leq π

cos (x) = 9054

1 + cos (2 x) = 2 sin^{2} (x)

6 sin^{2} (\frac{θ}{2}) = cos^{2} (θ) + 5

cos (x) = \frac{1}{4} - sin^{2} (x)

What is the general solution for cos(θ)=-sqrt(2/5) ?
The general solution for cos(θ)=-sqrt(2/5) is θ=2.25551…+2pin,θ=-2.25551…+2pin