What is the general solution for sin(x)= 1/8 ,sin(2x) ?

The general solution for sin(x)= 1/8 ,sin(2x) is No Solution for x\in\mathbb{R}

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sin(x)= 1/8 ,sin(2x)

sin (x) = \frac{1}{8}, sin (2 x)

No Solution for x \in R

Solution steps

sin (x) = \frac{1}{8}, sin (2 x)

Apply trig inverse properties

sin (x) = \frac{1}{8}

General solutions for

sin (x) = \frac{1}{8}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{1}{8}) + 2 πn, x = π - arcsin (\frac{1}{8}) + 2 πn

x = arcsin (\frac{1}{8}) + 2 πn, x = π - arcsin (\frac{1}{8}) + 2 πn

Solutions for the range

sin (2 x)

No Solution for x \in R

x, csc (x) = 2

\frac{3}{2} sec (x) = 3

9 (cos (a))^{2} - 9 (sin (a))^{2} = 0

1 - 2 cos^{2} (x) = 0, 0 \leq x \leq 2 π

2 sin (x - 2 0^{\circ}) + 1 = 0

What is the general solution for sin(x)= 1/8 ,sin(2x) ?
The general solution for sin(x)= 1/8 ,sin(2x) is No Solution for x\in\mathbb{R}