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Popular Trigonometria >

189.4=100tan^2(45+θ/2)

Solução

189.4 = 100 tan^{2} (4 5^{\circ} + \frac{θ}{2})

Solução

θ = 2 \cdot 0.94242 \dots + 36 0^{\circ} n - 9 0^{\circ}, θ = - 2 \cdot 0.94242 \dots + 36 0^{\circ} n - 9 0^{\circ}

Radianos

θ = 2 \cdot 0.94242 \dots - \frac{π}{2} + 2 πn, θ = - 2 \cdot 0.94242 \dots - \frac{π}{2} + 2 πn

Passos da solução

189.4 = 100 tan^{2} (4 5^{\circ} + \frac{θ}{2})

Trocar lados

100 tan^{2} (4 5^{\circ} + \frac{θ}{2}) = 189.4

Usando o método de substituição

100 tan^{2} (4 5^{\circ} + \frac{θ}{2}) = 189.4

Sea:

tan (4 5^{\circ} + \frac{θ}{2}) = u

100 u^{2} = 189.4

100 u^{2} = 189.4 : u = 1.894, u = - 1.894

100 u^{2} = 189.4

Dividir ambos os lados por

100

100 u^{2} = 189.4

Dividir ambos os lados por

100

\frac{100 u ^{2}}{100} = \frac{189.4}{100}

Simplificar

u^{2} = 1.894

u^{2} = 1.894

Para

x^{2} = f (a)

as soluções são

x = f (a), - f (a)

u = 1.894, u = - 1.894

Substituir na equação

u = tan (4 5^{\circ} + \frac{θ}{2})

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894, tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894, tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894 : θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894

Aplique as propriedades trigonométricas inversas

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894

Soluções gerais para

tan (4 5^{\circ} + \frac{θ}{2}) = 1.894

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

4 5^{\circ} + \frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n

4 5^{\circ} + \frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n

Resolver

4 5^{\circ} + \frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n : θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

4 5^{\circ} + \frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n

Mova

4 5^{\circ}

para o lado direito

4 5^{\circ} + \frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n

Subtrair

4 5^{\circ}

de ambos os lados

4 5^{\circ} + \frac{θ}{2} - 4 5^{\circ} = arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Simplificar

\frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

\frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Multiplicar ambos os lados por

2

\frac{θ}{2} = arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Multiplicar ambos os lados por

2

\frac{2 θ}{2} = 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

Simplificar

\frac{2 θ}{2} = 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

Simplificar

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

Dividir:

\frac{2}{2} = 1

= θ

Simplificar

2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ} : 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

2 \cdot 4 5^{\circ} = 9 0^{\circ}

2 \cdot 4 5^{\circ}

Multiplicar frações:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 9 0^{\circ}

Eliminar o fator comum:

2

= 9 0^{\circ}

= 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894 : θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894

Aplique as propriedades trigonométricas inversas

tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894

Soluções gerais para

tan (4 5^{\circ} + \frac{θ}{2}) = - 1.894

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

4 5^{\circ} + \frac{θ}{2} = arctan (- 1.894) + 18 0^{\circ} n

4 5^{\circ} + \frac{θ}{2} = arctan (- 1.894) + 18 0^{\circ} n

Resolver

4 5^{\circ} + \frac{θ}{2} = arctan (- 1.894) + 18 0^{\circ} n : θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

4 5^{\circ} + \frac{θ}{2} = arctan (- 1.894) + 18 0^{\circ} n

Simplificar

arctan (- 1.894) + 18 0^{\circ} n : - arctan (1.894) + 18 0^{\circ} n

arctan (- 1.894) + 18 0^{\circ} n

Utilizar a seguinte propriedade:

arctan (- x) = - arctan (x)

arctan (- 1.894) = - arctan (1.894)

= - arctan (1.894) + 18 0^{\circ} n

4 5^{\circ} + \frac{θ}{2} = - arctan (1.894) + 18 0^{\circ} n

Mova

4 5^{\circ}

para o lado direito

4 5^{\circ} + \frac{θ}{2} = - arctan (1.894) + 18 0^{\circ} n

Subtrair

4 5^{\circ}

de ambos os lados

4 5^{\circ} + \frac{θ}{2} - 4 5^{\circ} = - arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Simplificar

\frac{θ}{2} = - arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

\frac{θ}{2} = - arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Multiplicar ambos os lados por

2

\frac{θ}{2} = - arctan (1.894) + 18 0^{\circ} n - 4 5^{\circ}

Multiplicar ambos os lados por

2

\frac{2 θ}{2} = - 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

Simplificar

\frac{2 θ}{2} = - 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

Simplificar

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

Dividir:

\frac{2}{2} = 1

= θ

Simplificar

- 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ} : - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

- 2 arctan (1.894) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

2 \cdot 4 5^{\circ} = 9 0^{\circ}

2 \cdot 4 5^{\circ}

Multiplicar frações:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 9 0^{\circ}

Eliminar o fator comum:

2

= 9 0^{\circ}

= - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

Combinar toda as soluções

θ = 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}, θ = - 2 arctan (1.894) + 36 0^{\circ} n - 9 0^{\circ}

Mostrar soluções na forma decimal

θ = 2 \cdot 0.94242 \dots + 36 0^{\circ} n - 9 0^{\circ}, θ = - 2 \cdot 0.94242 \dots + 36 0^{\circ} n - 9 0^{\circ}

Gráfico

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