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人気のある三角関数 >

sqrt(2)=csc(x)cot(x)

解

2 = csc (x) cot (x)

解

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

+1

度

x = 4 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

解答ステップ

2 = csc (x) cot (x)

辺を交換する

csc (x) cot (x) = 2

両辺から

2

を引く

csc (x) cot (x) - 2 = 0

サイン, コサインで表わす

- 2 + cot (x) csc (x)

基本的な三角関数の公式を使用する:

cot (x) = \frac{cos ( x )}{sin ( x )}

= - 2 + \frac{cos ( x )}{sin ( x )} csc (x)

基本的な三角関数の公式を使用する:

csc (x) = \frac{1}{sin ( x )}

= - 2 + \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{sin ( x )}

簡素化

- 2 + \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{sin ( x )} : \frac{- 2 sin ^{2} ( x ) + cos ( x )}{sin ^{2} ( x )}

- 2 + \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{sin ( x )}

\frac{cos ( x )}{sin ( x )} \cdot \frac{1}{sin ( x )} = \frac{cos ( x )}{sin ^{2} ( x )}

\frac{cos ( x )}{sin ( x )} \cdot \frac{1}{sin ( x )}

分数を乗じる:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{cos ( x ) \cdot 1}{sin ( x ) sin ( x )}

乗算:

cos (x) \cdot 1 = cos (x)

= \frac{cos ( x )}{sin ( x ) sin ( x )}

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

数を足す:

1 + 1 = 2

= sin^{2} (x)

= \frac{cos ( x )}{sin ^{2} ( x )}

= - 2 + \frac{cos ( x )}{sin ^{2} ( x )}

元を分数に変換する:

2 = \frac{2 sin ^{2} ( x )}{sin ^{2} ( x )}

= - \frac{2 sin ^{2} ( x )}{sin ^{2} ( x )} + \frac{cos ( x )}{sin ^{2} ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 sin ^{2} ( x ) + cos ( x )}{sin ^{2} ( x )}

= \frac{- 2 sin ^{2} ( x ) + cos ( x )}{sin ^{2} ( x )}

\frac{cos ( x ) - sin ^{2} ( x ) 2}{sin ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (x) - sin^{2} (x) 2 = 0

三角関数の公式を使用して書き換える

cos (x) - sin^{2} (x) 2

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= cos (x) - (1 - cos^{2} (x)) 2

cos (x) - (1 - cos^{2} (x)) 2 = 0

置換で解く

cos (x) - (1 - cos^{2} (x)) 2 = 0

仮定:

cos (x) = u

u - (1 - u^{2}) 2 = 0

u - (1 - u^{2}) 2 = 0 : u = \frac{2}{2}, u = - 2

u - (1 - u^{2}) 2 = 0

拡張

u - (1 - u^{2}) 2 : u - 2 + 2 u^{2}

u - (1 - u^{2}) 2

= u - 2 (1 - u^{2})

拡張

- 2 (1 - u^{2}) : - 2 + 2 u^{2}

- 2 (1 - u^{2})

分配法則を適用する:

a (b - c) = ab - a c

a = - 2, b = 1, c = u^{2}

= - 2 \cdot 1 - (- 2) u^{2}

マイナス・プラスの規則を適用する

- (- a) = a

= - 1 \cdot 2 + 2 u^{2}

乗算:

1 \cdot 2 = 2

= - 2 + 2 u^{2}

= u - 2 + 2 u^{2}

u - 2 + 2 u^{2} = 0

標準的な形式で書く

a x^{2} + b x + c = 0

2 u^{2} + u - 2 = 0

解くとthe二次式

2 u^{2} + u - 2 = 0

二次Equationの公式:

次の場合:

a = 2, b = 1, c = - 2

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 2 ( - 2 )}{2 2}

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 2 ( - 2 )}{2 2}

1^{2} - 42 (- 2) = 3

1^{2} - 42 (- 2)

規則を適用

1^{a} = 1

1^{2} = 1

= 1 - 42 (- 2)

規則を適用

- (- a) = a

= 1 + 422

422 = 8

422

累乗根の規則を適用する:

a a = a

22 = 2

= 4 \cdot 2

数を乗じる:

4 \cdot 2 = 8

= 8

= 1 + 8

数を足す:

1 + 8 = 9

= 9

数を因数に分解する:

9 = 3^{2}

= 3^{2}

累乗根の規則を適用する:

3^{2} = 3

= 3

u_{1, 2} = \frac{- 1 \pm 3}{2 2}

解を分離する

u_{1} = \frac{- 1 + 3}{2 2}, u_{2} = \frac{- 1 - 3}{2 2}

u = \frac{- 1 + 3}{2 2} : \frac{2}{2}

\frac{- 1 + 3}{2 2}

数を足す/引く:

- 1 + 3 = 2

= \frac{2}{2 2}

数を割る:

\frac{2}{2} = 1

= \frac{1}{2}

有理化する

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

共役で乗じる

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

累乗根の規則を適用する:

a a = a

22 = 2

= 2

= \frac{2}{2}

= \frac{2}{2}

u = \frac{- 1 - 3}{2 2} : - 2

\frac{- 1 - 3}{2 2}

数を引く:

- 1 - 3 = - 4

= \frac{- 4}{2 2}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2 2}

数を割る:

\frac{4}{2} = 2

= \frac{2}{2}

累乗根の規則を適用する:

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

指数の規則を適用する:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

数を引く:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

累乗根の規則を適用する:

2^{\frac{1}{2}} = 2

= - 2

二次equationの解:

u = \frac{2}{2}, u = - 2

代用を戻す

u = cos (x)

cos (x) = \frac{2}{2}, cos (x) = - 2

cos (x) = \frac{2}{2}, cos (x) = - 2

cos (x) = \frac{2}{2} : x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

cos (x) = \frac{2}{2}

以下の一般解

cos (x) = \frac{2}{2}

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

cos (x) = - 2 :

解なし

cos (x) = - 2

- 1 \leq cos (x) \leq 1

解なし

すべての解を組み合わせる

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

グラフ

人気の例

5cos^2(θ)+3sqrt(2)sin(θ)-11/2 =0

cos^2(x)-5cos(x)+2=0

2sin^2(t)cos(t)=0

5sin(x)-12cos(x)=13