What is the general solution for tan(θ)= 8/15 ,sin(θ)>0 ?

The general solution for tan(θ)= 8/15 ,sin(θ)>0 is No Solution for θ\in\mathbb{R}

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tan(θ)= 8/15 ,sin(θ)>0

tan (θ) = \frac{8}{15}, sin (θ) > 0

No Solution for θ \in R

Solution steps

tan (θ) = \frac{8}{15}, sin (θ) > 0

Apply trig inverse properties

tan (θ) = \frac{8}{15}

General solutions for

tan (θ) = \frac{8}{15}

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (\frac{8}{15}) + πn

θ = arctan (\frac{8}{15}) + πn

Solutions for the range

sin (θ) > 0

No Solution for θ \in R

cos (x) = \frac{86.6}{100}

- 2 cos^{2} (θ) - 8 cos (θ) - 1 = - 5 cos (θ)

- 6 sin (θ) = - 33

2 sin (2 x) + cos (x) = 0

sin (d) = 0.81

What is the general solution for tan(θ)= 8/15 ,sin(θ)>0 ?
The general solution for tan(θ)= 8/15 ,sin(θ)>0 is No Solution for θ\in\mathbb{R}