What is the general solution for tan(x)+5=0,x<= 0<2pi ?

The general solution for tan(x)+5=0,x<= 0<2pi is No Solution for x\in\mathbb{R}

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tan(x)+5=0,x<= 0<2pi

tan (x) + 5 = 0, x \leq 0 < 2 π

No Solution for x \in R

Solution steps

tan (x) + 5 = 0, x \leq 0 < 2 π

Move

5

to the right side

tan (x) + 5 = 0

Subtract

5

from both sides

tan (x) + 5 - 5 = 0 - 5

Simplify

tan (x) = - 5

tan (x) = - 5

Apply trig inverse properties

tan (x) = - 5

General solutions for

tan (x) = - 5

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- 5) + πn

x = arctan (- 5) + πn

Solutions for the range

x \leq 0 < 2 π

No Solution for x \in R

\frac{31.5}{sin ( 57.2 2 ^{\circ} )} = \frac{24.4}{sin ( x )}

23 cos (θ - \frac{π}{3}) = 3, 0 \leq θ \leq 2 π

sin (6 x) = 1

3 sin (θ) = 2 cos (θ)

\frac{2}{2} = sin (x)

What is the general solution for tan(x)+5=0,x<= 0<2pi ?
The general solution for tan(x)+5=0,x<= 0<2pi is No Solution for x\in\mathbb{R}