What is the general solution for cos(θ)=-0.42,0<= θ<360 ?

The general solution for cos(θ)=-0.42,0<= θ<360 is θ=2.00424…,θ=4.27894…

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cos(θ)=-0.42,0<= θ<360

cos (θ) = - 0.42, 0^{\circ} \leq θ < 36 0^{\circ}

θ = 2.00424 \dots, θ = 4.27894 \dots

Solution steps

cos (θ) = - 0.42, 0^{\circ} \leq θ < 36 0^{\circ}

Apply trig inverse properties

cos (θ) = - 0.42

General solutions for

cos (θ) = - 0.42

cos (x) = - a \Rightarrow x = arccos (- a) + 36 0^{\circ} n, x = - arccos (- a) + 36 0^{\circ} n

θ = arccos (- 0.42) + 36 0^{\circ} n, θ = - arccos (- 0.42) + 36 0^{\circ} n

θ = arccos (- 0.42) + 36 0^{\circ} n, θ = - arccos (- 0.42) + 36 0^{\circ} n

Solutions for the range

0 \leq θ < 36 0^{\circ}

θ = 2.00424 \dots, θ = 4.27894 \dots

sin (2 x) = \frac{1}{2}, 0 < x < 2 π

4 sin^{2} (θ) + 2 cos (θ) = 3

\frac{1715}{70} = tan (4 5^{\circ} + \frac{θ}{2})

sin (θ) = - \frac{3}{2}, π < θ < \frac{3 π}{2}

cos (3 x) = sin (x - 3 0^{\circ})

What is the general solution for cos(θ)=-0.42,0<= θ<360 ?
The general solution for cos(θ)=-0.42,0<= θ<360 is θ=2.00424…,θ=4.27894…