What is the general solution for -sin(A)+2cos(A)sin(A)=0 ?

The general solution for -sin(A)+2cos(A)sin(A)=0 is A=2pin,A=pi+2pin,A= pi/3+2pin,A=(5pi)/3+2pin

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-sin(A)+2cos(A)sin(A)=0

- sin (A) + 2 cos (A) sin (A) = 0

A = 2 πn, A = π + 2 πn, A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

Degrees

A = 0^{\circ} + 36 0^{\circ} n, A = 18 0^{\circ} + 36 0^{\circ} n, A = 6 0^{\circ} + 36 0^{\circ} n, A = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

- sin (A) + 2 cos (A) sin (A) = 0

Factor

- sin (A) + 2 cos (A) sin (A) : sin (A) (2 cos (A) - 1)

- sin (A) + 2 cos (A) sin (A)

Factor out common term

sin (A)

= sin (A) (- 1 + 2 cos (A))

sin (A) (2 cos (A) - 1) = 0

Solving each part separately

sin (A) = 0 or 2 cos (A) - 1 = 0

sin (A) = 0 : A = 2 πn, A = π + 2 πn

sin (A) = 0

General solutions for

sin (A) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

A = 0 + 2 πn, A = π + 2 πn

A = 0 + 2 πn, A = π + 2 πn

Solve

A = 0 + 2 πn : A = 2 πn

A = 0 + 2 πn

0 + 2 πn = 2 πn

A = 2 πn

A = 2 πn, A = π + 2 πn

2 cos (A) - 1 = 0 : A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

2 cos (A) - 1 = 0

Move

1

to the right side

2 cos (A) - 1 = 0

Add

1

to both sides

2 cos (A) - 1 + 1 = 0 + 1

Simplify

2 cos (A) = 1

2 cos (A) = 1

Divide both sides by

2

2 cos (A) = 1

Divide both sides by

2

\frac{2 cos ( A )}{2} = \frac{1}{2}

Simplify

cos (A) = \frac{1}{2}

cos (A) = \frac{1}{2}

General solutions for

cos (A) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

Combine all the solutions

A = 2 πn, A = π + 2 πn, A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

sin (2 θ) = - \frac{1}{2}, \forall 0 \leq θ < 2 π

t, 2 - 2 cosh (t - 2) = 0

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

sin (x) = \frac{39}{62}

2 cot^{2} (x) - csc^{2} (x) + csc (x) = 4

What is the general solution for -sin(A)+2cos(A)sin(A)=0 ?
The general solution for -sin(A)+2cos(A)sin(A)=0 is A=2pin,A=pi+2pin,A= pi/3+2pin,A=(5pi)/3+2pin