What is the general solution for 3tan(θ)=-3,0<= θ<= 2pi ?

The general solution for 3tan(θ)=-3,0<= θ<= 2pi is θ=(3pi)/4 ,θ=(7pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

3tan(θ)=-3,0<= θ<= 2pi

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

Degrees

θ = 13 5^{\circ}, θ = 31 5^{\circ}

Solution steps

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

Divide both sides by

3

3 tan (θ) = - 3

Divide both sides by

3

\frac{3 tan ( θ )}{3} = \frac{- 3}{3}

Simplify

tan (θ) = - 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

What is the general solution for 3tan(θ)=-3,0<= θ<= 2pi ?
The general solution for 3tan(θ)=-3,0<= θ<= 2pi is θ=(3pi)/4 ,θ=(7pi)/4