What is the general solution for cos(u)= 2/5 ,cos(2u) ?

The general solution for cos(u)= 2/5 ,cos(2u) is No Solution for u\in\mathbb{R}

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cos(u)= 2/5 ,cos(2u)

cos (u) = \frac{2}{5}, cos (2 u)

No Solution for u \in R

Solution steps

cos (u) = \frac{2}{5}, cos (2 u)

Apply trig inverse properties

cos (u) = \frac{2}{5}

General solutions for

cos (u) = \frac{2}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

u = arccos (\frac{2}{5}) + 2 πn, u = 2 π - arccos (\frac{2}{5}) + 2 πn

u = arccos (\frac{2}{5}) + 2 πn, u = 2 π - arccos (\frac{2}{5}) + 2 πn

Solutions for the range

cos (2 u)

No Solution for u \in R

sin (b) = \frac{2}{2}

h = 7 cos (\frac{π}{3} t), t

3 + 3 sin (θ) = 3 + 3 cos (θ)

- 3 = tan (θ)

cot (θ) = 13

What is the general solution for cos(u)= 2/5 ,cos(2u) ?
The general solution for cos(u)= 2/5 ,cos(2u) is No Solution for u\in\mathbb{R}