What is the general solution for -sqrt(3)=tan(θ) ?

The general solution for -sqrt(3)=tan(θ) is θ=(2pi)/3+pin

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-sqrt(3)=tan(θ)

- 3 = tan (θ)

θ = \frac{2 π}{3} + πn

Degrees

θ = 12 0^{\circ} + 18 0^{\circ} n

Solution steps

- 3 = tan (θ)

Switch sides

tan (θ) = - 3

General solutions for

tan (θ) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{2 π}{3} + πn

θ = \frac{2 π}{3} + πn

cot (θ) = 13

arctan (0.2 x) + arctan (0.0625 x) = 5 4^{\circ}

sin^{2} (θ) + cos (θ) = 1

sin (θ) = \frac{- 12}{13}

tan (x) = (\frac{3}{4})

What is the general solution for -sqrt(3)=tan(θ) ?
The general solution for -sqrt(3)=tan(θ) is θ=(2pi)/3+pin