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Popular Trigonometry >

49.55cos(θ)-30sin(θ)=1.225

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Solution

49.55cos(θ)−30sin(θ)=1.225

Solution

θ=π+1.04752…+2πn,θ=1.00522…+2πn
+1
Degrees
θ=240.01903…∘+360∘n,θ=57.59542…∘+360∘n
Solution steps
49.55cos(θ)−30sin(θ)=1.225
Add 30sin(θ) to both sides49.55cos(θ)=1.225+30sin(θ)
Square both sides(49.55cos(θ))2=(1.225+30sin(θ))2
Subtract (1.225+30sin(θ))2 from both sides2455.2025cos2(θ)−1.500625−73.5sin(θ)−900sin2(θ)=0
Rewrite using trig identities
−1.500625+2455.2025cos2(θ)−73.5sin(θ)−900sin2(θ)
Use the Pythagorean identity: cos2(x)+sin2(x)=1cos2(x)=1−sin2(x)=−1.500625+2455.2025(1−sin2(θ))−73.5sin(θ)−900sin2(θ)
Simplify −1.500625+2455.2025(1−sin2(θ))−73.5sin(θ)−900sin2(θ):−3355.2025sin2(θ)−73.5sin(θ)+2453.701875
−1.500625+2455.2025(1−sin2(θ))−73.5sin(θ)−900sin2(θ)
Expand 2455.2025(1−sin2(θ)):2455.2025−2455.2025sin2(θ)
2455.2025(1−sin2(θ))
Apply the distributive law: a(b−c)=ab−aca=2455.2025,b=1,c=sin2(θ)=2455.2025⋅1−2455.2025sin2(θ)
=1⋅2455.2025−2455.2025sin2(θ)
Multiply the numbers: 1⋅2455.2025=2455.2025=2455.2025−2455.2025sin2(θ)
=−1.500625+2455.2025−2455.2025sin2(θ)−73.5sin(θ)−900sin2(θ)
Simplify −1.500625+2455.2025−2455.2025sin2(θ)−73.5sin(θ)−900sin2(θ):−3355.2025sin2(θ)−73.5sin(θ)+2453.701875
−1.500625+2455.2025−2455.2025sin2(θ)−73.5sin(θ)−900sin2(θ)
Group like terms=−2455.2025sin2(θ)−73.5sin(θ)−900sin2(θ)−1.500625+2455.2025
Add similar elements: −2455.2025sin2(θ)−900sin2(θ)=−3355.2025sin2(θ)=−3355.2025sin2(θ)−73.5sin(θ)−1.500625+2455.2025
Add/Subtract the numbers: −1.500625+2455.2025=2453.701875=−3355.2025sin2(θ)−73.5sin(θ)+2453.701875
=−3355.2025sin2(θ)−73.5sin(θ)+2453.701875
=−3355.2025sin2(θ)−73.5sin(θ)+2453.701875
2453.701875−3355.2025sin2(θ)−73.5sin(θ)=0
Solve by substitution
2453.701875−3355.2025sin2(θ)−73.5sin(θ)=0
Let: sin(θ)=u2453.701875−3355.2025u2−73.5u=0
2453.701875−3355.2025u2−73.5u=0:u=−6710.40573.5+32936068.91101…​​,u=6710.40532936068.91101…​−73.5​
2453.701875−3355.2025u2−73.5u=0
Write in the standard form ax2+bx+c=0−3355.2025u2−73.5u+2453.701875=0
Solve with the quadratic formula
−3355.2025u2−73.5u+2453.701875=0
Quadratic Equation Formula:
For a=−3355.2025,b=−73.5,c=2453.701875u1,2​=2(−3355.2025)−(−73.5)±(−73.5)2−4(−3355.2025)⋅2453.701875​​
u1,2​=2(−3355.2025)−(−73.5)±(−73.5)2−4(−3355.2025)⋅2453.701875​​
(−73.5)2−4(−3355.2025)⋅2453.701875​=32936068.91101…​
(−73.5)2−4(−3355.2025)⋅2453.701875​
Apply rule −(−a)=a=(−73.5)2+4⋅3355.2025⋅2453.701875​
Apply exponent rule: (−a)n=an,if n is even(−73.5)2=73.52=73.52+4⋅2453.701875⋅3355.2025​
Multiply the numbers: 4⋅3355.2025⋅2453.701875=32930666.66101…=73.52+32930666.66101…​
73.52=5402.25=5402.25+32930666.66101…​
Add the numbers: 5402.25+32930666.66101…=32936068.91101…=32936068.91101…​
u1,2​=2(−3355.2025)−(−73.5)±32936068.91101…​​
Separate the solutionsu1​=2(−3355.2025)−(−73.5)+32936068.91101…​​,u2​=2(−3355.2025)−(−73.5)−32936068.91101…​​
u=2(−3355.2025)−(−73.5)+32936068.91101…​​:−6710.40573.5+32936068.91101…​​
2(−3355.2025)−(−73.5)+32936068.91101…​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅3355.202573.5+32936068.91101…​​
Multiply the numbers: 2⋅3355.2025=6710.405=−6710.40573.5+32936068.91101…​​
Apply the fraction rule: −ba​=−ba​=−6710.40573.5+32936068.91101…​​
u=2(−3355.2025)−(−73.5)−32936068.91101…​​:6710.40532936068.91101…​−73.5​
2(−3355.2025)−(−73.5)−32936068.91101…​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅3355.202573.5−32936068.91101…​​
Multiply the numbers: 2⋅3355.2025=6710.405=−6710.40573.5−32936068.91101…​​
Apply the fraction rule: −b−a​=ba​73.5−32936068.91101…​=−(32936068.91101…​−73.5)=6710.40532936068.91101…​−73.5​
The solutions to the quadratic equation are:u=−6710.40573.5+32936068.91101…​​,u=6710.40532936068.91101…​−73.5​
Substitute back u=sin(θ)sin(θ)=−6710.40573.5+32936068.91101…​​,sin(θ)=6710.40532936068.91101…​−73.5​
sin(θ)=−6710.40573.5+32936068.91101…​​,sin(θ)=6710.40532936068.91101…​−73.5​
sin(θ)=−6710.40573.5+32936068.91101…​​:θ=arcsin(−6710.40573.5+32936068.91101…​​)+2πn,θ=π+arcsin(6710.40573.5+32936068.91101…​​)+2πn
sin(θ)=−6710.40573.5+32936068.91101…​​
Apply trig inverse properties
sin(θ)=−6710.40573.5+32936068.91101…​​
General solutions for sin(θ)=−6710.40573.5+32936068.91101…​​sin(x)=−a⇒x=arcsin(−a)+2πn,x=π+arcsin(a)+2πnθ=arcsin(−6710.40573.5+32936068.91101…​​)+2πn,θ=π+arcsin(6710.40573.5+32936068.91101…​​)+2πn
θ=arcsin(−6710.40573.5+32936068.91101…​​)+2πn,θ=π+arcsin(6710.40573.5+32936068.91101…​​)+2πn
sin(θ)=6710.40532936068.91101…​−73.5​:θ=arcsin(6710.40532936068.91101…​−73.5​)+2πn,θ=π−arcsin(6710.40532936068.91101…​−73.5​)+2πn
sin(θ)=6710.40532936068.91101…​−73.5​
Apply trig inverse properties
sin(θ)=6710.40532936068.91101…​−73.5​
General solutions for sin(θ)=6710.40532936068.91101…​−73.5​sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πnθ=arcsin(6710.40532936068.91101…​−73.5​)+2πn,θ=π−arcsin(6710.40532936068.91101…​−73.5​)+2πn
θ=arcsin(6710.40532936068.91101…​−73.5​)+2πn,θ=π−arcsin(6710.40532936068.91101…​−73.5​)+2πn
Combine all the solutionsθ=arcsin(−6710.40573.5+32936068.91101…​​)+2πn,θ=π+arcsin(6710.40573.5+32936068.91101…​​)+2πn,θ=arcsin(6710.40532936068.91101…​−73.5​)+2πn,θ=π−arcsin(6710.40532936068.91101…​−73.5​)+2πn
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into 49.55cos(θ)−30sin(θ)=1.225
Remove the ones that don't agree with the equation.
Check the solution arcsin(−6710.40573.5+32936068.91101…​​)+2πn:False
arcsin(−6710.40573.5+32936068.91101…​​)+2πn
Plug in n=1arcsin(−6710.40573.5+32936068.91101…​​)+2π1
For 49.55cos(θ)−30sin(θ)=1.225plug inθ=arcsin(−6710.40573.5+32936068.91101…​​)+2π149.55cos(arcsin(−6710.40573.5+32936068.91101…​​)+2π1)−30sin(arcsin(−6710.40573.5+32936068.91101…​​)+2π1)=1.225
Refine50.74648…=1.225
⇒False
Check the solution π+arcsin(6710.40573.5+32936068.91101…​​)+2πn:True
π+arcsin(6710.40573.5+32936068.91101…​​)+2πn
Plug in n=1π+arcsin(6710.40573.5+32936068.91101…​​)+2π1
For 49.55cos(θ)−30sin(θ)=1.225plug inθ=π+arcsin(6710.40573.5+32936068.91101…​​)+2π149.55cos(π+arcsin(6710.40573.5+32936068.91101…​​)+2π1)−30sin(π+arcsin(6710.40573.5+32936068.91101…​​)+2π1)=1.225
Refine1.22499…=1.225
⇒True
Check the solution arcsin(6710.40532936068.91101…​−73.5​)+2πn:True
arcsin(6710.40532936068.91101…​−73.5​)+2πn
Plug in n=1arcsin(6710.40532936068.91101…​−73.5​)+2π1
For 49.55cos(θ)−30sin(θ)=1.225plug inθ=arcsin(6710.40532936068.91101…​−73.5​)+2π149.55cos(arcsin(6710.40532936068.91101…​−73.5​)+2π1)−30sin(arcsin(6710.40532936068.91101…​−73.5​)+2π1)=1.225
Refine1.225=1.225
⇒True
Check the solution π−arcsin(6710.40532936068.91101…​−73.5​)+2πn:False
π−arcsin(6710.40532936068.91101…​−73.5​)+2πn
Plug in n=1π−arcsin(6710.40532936068.91101…​−73.5​)+2π1
For 49.55cos(θ)−30sin(θ)=1.225plug inθ=π−arcsin(6710.40532936068.91101…​−73.5​)+2π149.55cos(π−arcsin(6710.40532936068.91101…​−73.5​)+2π1)−30sin(π−arcsin(6710.40532936068.91101…​−73.5​)+2π1)=1.225
Refine−51.88211…=1.225
⇒False
θ=π+arcsin(6710.40573.5+32936068.91101…​​)+2πn,θ=arcsin(6710.40532936068.91101…​−73.5​)+2πn
Show solutions in decimal formθ=π+1.04752…+2πn,θ=1.00522…+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for 49.55cos(θ)-30sin(θ)=1.225 ?

    The general solution for 49.55cos(θ)-30sin(θ)=1.225 is θ=pi+1.04752…+2pin,θ=1.00522…+2pin
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