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Popular Trigonometry >

sin(2x-20)=-cos(3x+50)

  • Pre Algebra
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Solution

sin(2x−20)=−cos(3x+50)

Solution

x=2πn+2π​−70,x=−104πn+60+π​
+1
Degrees
x=−3920.70456…∘+360∘n,x=−361.77467…∘−72∘n
Solution steps
sin(2x−20)=−cos(3x+50)
Multiply by −1−sin(2x−20)=cos(3x+50)
Rewrite using trig identities
−sin(2x−20)=cos(3x+50)
Use the following identity: −sin(x)=sin(−x)sin(−(2x−20))=cos(3x+50)
Use the following identity: cos(x)=sin(2π​−x)sin(−(2x−20))=sin(2π​−(3x+50))
sin(−(2x−20))=sin(2π​−(3x+50))
Apply trig inverse properties
sin(−(2x−20))=sin(2π​−(3x+50))
sin(x)=sin(y)⇒x=y+2πn,x=π−y+2πn−(2x−20)=2π​−(3x+50)+2πn,−(2x−20)=π−(2π​−(3x+50))+2πn
−(2x−20)=2π​−(3x+50)+2πn,−(2x−20)=π−(2π​−(3x+50))+2πn
−(2x−20)=2π​−(3x+50)+2πn:x=2πn+2π​−70
−(2x−20)=2π​−(3x+50)+2πn
Expand −(2x−20):−2x+20
−(2x−20)
Distribute parentheses=−(2x)−(−20)
Apply minus-plus rules−(−a)=a,−(a)=−a=−2x+20
Expand 2π​−(3x+50)+2πn:2π​−3x−50+2πn
2π​−(3x+50)+2πn
−(3x+50):−3x−50
−(3x+50)
Distribute parentheses=−(3x)−(50)
Apply minus-plus rules+(−a)=−a=−3x−50
=2π​−3x−50+2πn
−2x+20=2π​−3x−50+2πn
Move 20to the right side
−2x+20=2π​−3x−50+2πn
Subtract 20 from both sides−2x+20−20=2π​−3x−50+2πn−20
Simplify
−2x+20−20=2π​−3x−50+2πn−20
Simplify −2x+20−20:−2x
−2x+20−20
Add similar elements: 20−20=0
=−2x
Simplify 2π​−3x−50+2πn−20:−3x+2πn+2π​−70
2π​−3x−50+2πn−20
Group like terms=−3x+2πn+2π​−50−20
Subtract the numbers: −50−20=−70=−3x+2πn+2π​−70
−2x=−3x+2πn+2π​−70
−2x=−3x+2πn+2π​−70
−2x=−3x+2πn+2π​−70
Move 3xto the left side
−2x=−3x+2πn+2π​−70
Add 3x to both sides−2x+3x=−3x+2πn+2π​−70+3x
Simplifyx=2πn+2π​−70
x=2πn+2π​−70
−(2x−20)=π−(2π​−(3x+50))+2πn:x=−104πn+60+π​
−(2x−20)=π−(2π​−(3x+50))+2πn
Expand −(2x−20):−2x+20
−(2x−20)
Distribute parentheses=−(2x)−(−20)
Apply minus-plus rules−(−a)=a,−(a)=−a=−2x+20
Expand π−(2π​−(3x+50))+2πn:π−2π​+3x+50+2πn
π−(2π​−(3x+50))+2πn
−(3x+50):−3x−50
−(3x+50)
Distribute parentheses=−(3x)−(50)
Apply minus-plus rules+(−a)=−a=−3x−50
=π−(−3x+2π​−50)+2πn
−(2π​−3x−50):−2π​+3x+50
−(2π​−3x−50)
Distribute parentheses=−(2π​)−(−3x)−(−50)
Apply minus-plus rules−(−a)=a,−(a)=−a=−2π​+3x+50
=π−2π​+3x+50+2πn
−2x+20=π−2π​+3x+50+2πn
Move 20to the right side
−2x+20=π−2π​+3x+50+2πn
Subtract 20 from both sides−2x+20−20=π−2π​+3x+50+2πn−20
Simplify
−2x+20−20=π−2π​+3x+50+2πn−20
Simplify −2x+20−20:−2x
−2x+20−20
Add similar elements: 20−20=0
=−2x
Simplify π−2π​+3x+50+2πn−20:3x+2πn+30+π−2π​
π−2π​+3x+50+2πn−20
Group like terms=3x+π+2πn−2π​+50−20
Add/Subtract the numbers: 50−20=30=3x+2πn+30+π−2π​
−2x=3x+2πn+30+π−2π​
−2x=3x+2πn+30+π−2π​
−2x=3x+2πn+30+π−2π​
Move 3xto the left side
−2x=3x+2πn+30+π−2π​
Subtract 3x from both sides−2x−3x=3x+2πn+30+π−2π​−3x
Simplify−5x=2πn+30+π−2π​
−5x=2πn+30+π−2π​
Divide both sides by −5
−5x=2πn+30+π−2π​
Divide both sides by −5−5−5x​=−52πn​+−530​+−5π​−−52π​​
Simplify
−5−5x​=−52πn​+−530​+−5π​−−52π​​
Simplify −5−5x​:x
−5−5x​
Apply the fraction rule: −b−a​=ba​=55x​
Divide the numbers: 55​=1=x
Simplify −52πn​+−530​+−5π​−−52π​​:−104πn+60+π​
−52πn​+−530​+−5π​−−52π​​
Apply rule ca​±cb​=ca±b​=−52πn+30+π−2π​​
Apply the fraction rule: −ba​=−ba​=−52πn+30+π−2π​​
Join 2πn+30+π−2π​:24πn+60+π​
2πn+30+π−2π​
Convert element to fraction: 2πn=22πn2​,30=230⋅2​,π=2π2​=22πn⋅2​+230⋅2​+2π2​−2π​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=22πn⋅2+30⋅2+π2−π​
2πn⋅2+30⋅2+π2−π=4πn+60+π
2πn⋅2+30⋅2+π2−π
Add similar elements: 2π−π=π=2⋅2πn+30⋅2+π
Multiply the numbers: 2⋅2=4=4πn+30⋅2+π
Multiply the numbers: 30⋅2=60=4πn+60+π
=24πn+60+π​
=−524πn+π+60​​
Simplify 524πn+60+π​​:104πn+60+π​
524πn+60+π​​
Apply the fraction rule: acb​​=c⋅ab​=2⋅54πn+60+π​
Multiply the numbers: 2⋅5=10=104πn+60+π​
=−104πn+π+60​
=−104πn+60+π​
x=−104πn+60+π​
x=−104πn+60+π​
x=−104πn+60+π​
x=2πn+2π​−70,x=−104πn+60+π​
x=2πn+2π​−70,x=−104πn+60+π​

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(sin(60))/(174.36)=(sin(x))/(200)cos(x)= 8/13cos^2(4x)-sin^2(4x)=0cos(x)= 8/15sin(4k-22)=cos(6k-13)

Frequently Asked Questions (FAQ)

  • What is the general solution for sin(2x-20)=-cos(3x+50) ?

    The general solution for sin(2x-20)=-cos(3x+50) is x=2pin+pi/2-70,x=-(4pin+60+pi)/(10)
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