{
"query": {
"display": "$$\\tan\\left(2θ\\right)=0.55$$",
"symbolab_question": "EQUATION#\\tan(2θ)=0.55"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "θ=\\frac{0.50284…}{2}+\\frac{πn}{2}",
"degrees": "θ=14.40539…^{\\circ }+90^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\tan\\left(2θ\\right)=0.55{\\quad:\\quad}θ=\\frac{0.50284…}{2}+\\frac{πn}{2}$$",
"input": "\\tan\\left(2θ\\right)=0.55",
"steps": [
{
"type": "interim",
"title": "Apply trig inverse properties",
"input": "\\tan\\left(2θ\\right)=0.55",
"result": "2θ=\\arctan\\left(0.55\\right)+πn",
"steps": [
{
"type": "step",
"primary": "General solutions for $$\\tan\\left(2θ\\right)=0.55$$",
"secondary": [
"$$\\tan\\left(x\\right)=a\\quad\\Rightarrow\\quad\\:x=\\arctan\\left(a\\right)+πn$$"
],
"result": "2θ=\\arctan\\left(0.55\\right)+πn"
}
],
"meta": {
"interimType": "Trig Apply Inverse Props 0Eq"
}
},
{
"type": "interim",
"title": "Solve $$2θ=\\arctan\\left(0.55\\right)+πn:{\\quad}θ=\\frac{\\arctan\\left(0.55\\right)}{2}+\\frac{πn}{2}$$",
"input": "2θ=\\arctan\\left(0.55\\right)+πn",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2θ=\\arctan\\left(0.55\\right)+πn",
"result": "θ=\\frac{\\arctan\\left(0.55\\right)}{2}+\\frac{πn}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2θ}{2}=\\frac{\\arctan\\left(0.55\\right)}{2}+\\frac{πn}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "θ=\\frac{\\arctan\\left(0.55\\right)}{2}+\\frac{πn}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "θ=\\frac{\\arctan\\left(0.55\\right)}{2}+\\frac{πn}{2}"
},
{
"type": "step",
"primary": "Show solutions in decimal form",
"result": "θ=\\frac{0.50284…}{2}+\\frac{πn}{2}"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "θ",
"plotRequest": "\\tan(2θ)-0.55"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Apply trig inverse properties
General solutions for
Solve
Divide both sides by
Divide both sides by
Simplify
Show solutions in decimal form
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for tan(2θ)=0.55 ?
The general solution for tan(2θ)=0.55 is θ=(0.50284…)/2+(pin)/2