What is the general solution for 1-2cos(x)=0,(0,2pi) ?

The general solution for 1-2cos(x)=0,(0,2pi) is x= pi/3 ,x=(5pi)/3

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1-2cos(x)=0,(0,2pi)

1 - 2 cos (x) = 0, (0, 2 π)

x = \frac{π}{3}, x = \frac{5 π}{3}

Degrees

x = 6 0^{\circ}, x = 30 0^{\circ}

Solution steps

1 - 2 cos (x) = 0, (0, 2 π)

Move

1

to the right side

1 - 2 cos (x) = 0

Subtract

1

from both sides

1 - 2 cos (x) - 1 = 0 - 1

Simplify

- 2 cos (x) = - 1

- 2 cos (x) = - 1

Divide both sides by

- 2

- 2 cos (x) = - 1

Divide both sides by

- 2

\frac{- 2 cos ( x )}{- 2} = \frac{- 1}{- 2}

Simplify

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

(0, 2 π)

x = \frac{π}{3}, x = \frac{5 π}{3}

8 sin (t) = 4

0.56 = tan^{2} (4 5^{\circ} + \frac{x}{2})

cos (2 x) = - 3

5 sec^{2} (x) - 14 tan (x) = 8

5 - 6 cos (x) = 0

What is the general solution for 1-2cos(x)=0,(0,2pi) ?
The general solution for 1-2cos(x)=0,(0,2pi) is x= pi/3 ,x=(5pi)/3