What is the general solution for tan(θ)=-4/5 , pi/2 <θ<pi ?

The general solution for tan(θ)=-4/5 , pi/2 <θ<pi is θ=-0.67474…+pi

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tan(θ)=-4/5 , pi/2 <θ<pi

tan (θ) = - \frac{4}{5}, \frac{π}{2} < θ < π

θ = - 0.67474 \dots + π

Degrees

θ = 141.34019 \dots^{\circ}

Solution steps

tan (θ) = - \frac{4}{5}, \frac{π}{2} < θ < π

Apply trig inverse properties

tan (θ) = - \frac{4}{5}

General solutions for

tan (θ) = - \frac{4}{5}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{4}{5}) + πn

θ = arctan (- \frac{4}{5}) + πn

Solutions for the range

\frac{π}{2} < θ < π

θ = - arctan (\frac{4}{5}) + π

Show solutions in decimal form

θ = - 0.67474 \dots + π

cos (2 x) = sin (x), 0 \leq x < 2 π

θ, x = sec (θ)

sin (x) + cos (x) = - 1, 0 \leq x \leq 2 π

229 cos (a) + 14715 sin (a) = 3959.55

sin (x) + 0.3 = \frac{cos ( x )}{2}

What is the general solution for tan(θ)=-4/5 , pi/2 <θ<pi ?
The general solution for tan(θ)=-4/5 , pi/2 <θ<pi is θ=-0.67474…+pi