What is the general solution for arccos(x)=arcsin(1/3)+arcsin(7/9) ?

The general solution for arccos(x)=arcsin(1/3)+arcsin(7/9) is x=cos(0.33983…+0.89112…)

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arccos(x)=arcsin(1/3)+arcsin(7/9)

arccos (x) = arcsin (\frac{1}{3}) + arcsin (\frac{7}{9})

x = cos (0.33983 \dots + 0.89112 \dots)

Solution steps

arccos (x) = arcsin (\frac{1}{3}) + arcsin (\frac{7}{9})

Apply trig inverse properties

arccos (x) = arcsin (\frac{1}{3}) + arcsin (\frac{7}{9})

arccos (x) = a \Rightarrow x = cos (a)

x = cos (arcsin (\frac{1}{3}) + arcsin (\frac{7}{9}))

x = cos (arcsin (\frac{1}{3}) + arcsin (\frac{7}{9}))

Show solutions in decimal form

x = cos (0.33983 \dots + 0.89112 \dots)

sin^{2} (2 x) = 2 sin^{2} (x) cos^{2} (x)

tan (θ) = - \frac{1}{5}

\frac{sin ( 7 0 ^{\circ} )}{25} = \frac{sin ( c )}{26}

\frac{csc ( x )}{2} = 3

cos (2 x) = sin (x) - 2

What is the general solution for arccos(x)=arcsin(1/3)+arcsin(7/9) ?
The general solution for arccos(x)=arcsin(1/3)+arcsin(7/9) is x=cos(0.33983…+0.89112…)