What is the general solution for 1+2sin(x)=1 ?

The general solution for 1+2sin(x)=1 is x=2pin,x=pi+2pin

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1+2sin(x)=1

1 + 2 sin (x) = 1

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

1 + 2 sin (x) = 1

Subtract

1

from both sides

1 + 2 sin (x) - 1 = 1 - 1

Simplify

2 sin (x) = 0

Divide both sides by

2

2 sin (x) = 0

Divide both sides by

2

\frac{2 sin ( x )}{2} = \frac{0}{2}

Simplify

sin (x) = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

sec^{2} (x) + cos (x) = - 1

sin (x) = - 0.465

cos (x) = \frac{10}{17}

θ, r = \frac{7}{1 + cos ( θ )}

What is the general solution for 1+2sin(x)=1 ?
The general solution for 1+2sin(x)=1 is x=2pin,x=pi+2pin