What is the general solution for arctan(0.0625x)+arctan(0.2x)=54 ?

The general solution for arctan(0.0625x)+arctan(0.2x)=54 is x=(sqrt(65.45104…)-5.25)/(0.68819…)

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arctan(0.0625x)+arctan(0.2x)=54

Solution

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

Solution

x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

Solution steps

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

Rewrite using trig identities

arctan (0.0625 x) + arctan (0.2 x)

Use the Sum to Product identity:

arctan (s) + arctan (t) = arctan (\frac{s + t}{1 - s t})

= arctan (\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x})

arctan (\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x}) = 5 4^{\circ}

Apply trig inverse properties

arctan (\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x}) = 5 4^{\circ}

arctan (x) = a \Rightarrow x = tan (a)

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = tan (5 4^{\circ})

tan (5 4^{\circ}) = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

tan (5 4^{\circ})

Rewrite using trig identities:

\frac{sin ( 5 4 ^{\circ} )}{cos ( 5 4 ^{\circ} )}

tan (5 4^{\circ})

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{sin ( 5 4 ^{\circ} )}{cos ( 5 4 ^{\circ} )}

= \frac{sin ( 5 4 ^{\circ} )}{cos ( 5 4 ^{\circ} )}

Rewrite using trig identities:

sin (5 4^{\circ}) = \frac{5 + 1}{4}

sin (5 4^{\circ})

Rewrite using trig identities:

cos (3 6^{\circ})

sin (5 4^{\circ})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

= cos (9 0^{\circ} - 5 4^{\circ})

Simplify:

9 0^{\circ} - 5 4^{\circ} = 3 6^{\circ}

9 0^{\circ} - 5 4^{\circ}

Least Common Multiplier of

2, 10 : 10

2, 10

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

10 : 2 \cdot 5

10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 5

Multiply each factor the greatest number of times it occurs in either

2

10

= 2 \cdot 5

Multiply the numbers:

2 \cdot 5 = 10

= 10

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

10

For

9 0^{\circ} :

multiply the denominator and numerator by

5

9 0^{\circ} = \frac{18 0 ^{\circ} 5}{2 \cdot 5} = 9 0^{\circ}

= 9 0^{\circ} - 5 4^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 5 - 54 0 ^{\circ}}{10}

Add similar elements:

90 0^{\circ} - 54 0^{\circ} = 36 0^{\circ}

= 3 6^{\circ}

Cancel the common factor:

2

= 3 6^{\circ}

= cos (3 6^{\circ})

= cos (3 6^{\circ})

Rewrite using trig identities:

\frac{5 + 1}{4}

cos (3 6^{\circ})

Show that:

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

Use the following product to sum identity:

2 sin (x) cos (y) = sin (x + y) - sin (x - y)

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = sin (5 4^{\circ}) - sin (1 8^{\circ})

Show that:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Divide both sides by

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Substitute

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

\frac{1}{2} = sin (5 4^{\circ}) - sin (1 8^{\circ})

sin (5 4^{\circ}) = cos (9 0^{\circ} - 5 4^{\circ})

\frac{1}{2} = cos (9 0^{\circ} - 5 4^{\circ}) - sin (1 8^{\circ})

\frac{1}{2} = cos (3 6^{\circ}) - sin (1 8^{\circ})

Show that:

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Use the factorization rule:

a^{2} - b^{2} = (a + b) (a - b)

a = cos (3 6^{\circ}) + sin (1 8^{\circ})

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = ((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) ((cos (3 6^{\circ}) + sin (1 8^{\circ})) - (cos (3 6^{\circ}) - sin (1 8^{\circ})))

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 2 (2 cos (3 6^{\circ}) sin (1 8^{\circ}))

Show that:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Divide both sides by

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Substitute

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 1

Substitute

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (\frac{1}{2})^{2} = 1

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} = 1

Add

\frac{1}{4}

to both sides

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} + \frac{1}{4} = 1 + \frac{1}{4}

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} = \frac{5}{4}

Take the square root of both sides

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \pm \frac{5}{4}

cos (3 6^{\circ})

cannot be negative

sin (1 8^{\circ})

cannot be negative

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Add the following equations

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{2}

((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) = (\frac{5}{2} + \frac{1}{2})

Refine

cos (3 6^{\circ}) = \frac{5 + 1}{4}

= \frac{5 + 1}{4}

= \frac{5 + 1}{4}

Rewrite using trig identities:

cos (5 4^{\circ}) = \frac{2 5 - 5}{4}

cos (5 4^{\circ})

Rewrite using trig identities:

sin (3 6^{\circ})

cos (5 4^{\circ})

Use the following identity:

cos (x) = sin (9 0^{\circ} - x)

= sin (9 0^{\circ} - 5 4^{\circ})

Simplify:

9 0^{\circ} - 5 4^{\circ} = 3 6^{\circ}

9 0^{\circ} - 5 4^{\circ}

Least Common Multiplier of

2, 10 : 10

2, 10

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

10 : 2 \cdot 5

10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 5

Multiply each factor the greatest number of times it occurs in either

2

10

= 2 \cdot 5

Multiply the numbers:

2 \cdot 5 = 10

= 10

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

10

For

9 0^{\circ} :

multiply the denominator and numerator by

5

9 0^{\circ} = \frac{18 0 ^{\circ} 5}{2 \cdot 5} = 9 0^{\circ}

= 9 0^{\circ} - 5 4^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 5 - 54 0 ^{\circ}}{10}

Add similar elements:

90 0^{\circ} - 54 0^{\circ} = 36 0^{\circ}

= 3 6^{\circ}

Cancel the common factor:

2

= 3 6^{\circ}

= sin (3 6^{\circ})

= sin (3 6^{\circ})

Rewrite using trig identities:

\frac{2 5 - 5}{4}

sin (3 6^{\circ})

Show that:

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

Use the following product to sum identity:

2 sin (x) cos (y) = sin (x + y) - sin (x - y)

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = sin (5 4^{\circ}) - sin (1 8^{\circ})

Show that:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Divide both sides by

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Substitute

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

\frac{1}{2} = sin (5 4^{\circ}) - sin (1 8^{\circ})

sin (5 4^{\circ}) = cos (9 0^{\circ} - 5 4^{\circ})

\frac{1}{2} = cos (9 0^{\circ} - 5 4^{\circ}) - sin (1 8^{\circ})

\frac{1}{2} = cos (3 6^{\circ}) - sin (1 8^{\circ})

Show that:

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Use the factorization rule:

a^{2} - b^{2} = (a + b) (a - b)

a = cos (3 6^{\circ}) + sin (1 8^{\circ})

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = ((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) ((cos (3 6^{\circ}) + sin (1 8^{\circ})) - (cos (3 6^{\circ}) - sin (1 8^{\circ})))

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 2 (2 cos (3 6^{\circ}) sin (1 8^{\circ}))

Show that:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Divide both sides by

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Divide both sides by

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Substitute

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 1

Substitute

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (\frac{1}{2})^{2} = 1

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} = 1

Add

\frac{1}{4}

to both sides

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} + \frac{1}{4} = 1 + \frac{1}{4}

Refine

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} = \frac{5}{4}

Take the square root of both sides

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \pm \frac{5}{4}

cos (3 6^{\circ})

cannot be negative

sin (1 8^{\circ})

cannot be negative

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Add the following equations

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{2}

((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) = (\frac{5}{2} + \frac{1}{2})

Refine

cos (3 6^{\circ}) = \frac{5 + 1}{4}

Square both sides

(cos (3 6^{\circ}))^{2} = (\frac{5 + 1}{4})^{2}

Use the following identity:

sin^{2} (x) = 1 - cos^{2} (x)

sin^{2} (3 6^{\circ}) = 1 - cos^{2} (3 6^{\circ})

Substitute

cos (3 6^{\circ}) = \frac{5 + 1}{4}

sin^{2} (3 6^{\circ}) = 1 - (\frac{5 + 1}{4})^{2}

Refine

sin^{2} (3 6^{\circ}) = \frac{5 - 5}{8}

Take the square root of both sides

sin (3 6^{\circ}) = \pm \frac{5 - 5}{8}

sin (3 6^{\circ})

cannot be negative

sin (3 6^{\circ}) = \frac{5 - 5}{8}

Refine

sin (3 6^{\circ}) = \frac{\frac{5 - 5}{2}}{2}

= \frac{\frac{5 - 5}{2}}{2}

\frac{\frac{5 - 5}{2}}{2} = \frac{2 5 - 5}{4}

\frac{\frac{5 - 5}{2}}{2}

\frac{5 - 5}{2} = \frac{5 - 5}{2}

\frac{5 - 5}{2}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{5 - 5}{2}

= \frac{\frac{5 - 5}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 - 5}{2 \cdot 2}

Rationalize

\frac{5 - 5}{2 2} : \frac{2 5 - 5}{4}

\frac{5 - 5}{2 2}

Multiply by the conjugate

\frac{2}{2}

= \frac{5 - 5 2}{2 \cdot 2 2}

2 \cdot 22 = 4

2 \cdot 22

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

222 = 2 \cdot 2^{\frac{1}{2}} \cdot 2^{\frac{1}{2}} = 2^{1 + \frac{1}{2} + \frac{1}{2}}

= 2^{1 + \frac{1}{2} + \frac{1}{2}}

Add similar elements:

\frac{1}{2} + \frac{1}{2} = 2 \cdot \frac{1}{2}

= 2^{1 + 2 \cdot \frac{1}{2}}

2 \cdot \frac{1}{2} = 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2^{1 + 1}

Add the numbers:

1 + 1 = 2

= 2^{2}

2^{2} = 4

= 4

= \frac{2 5 - 5}{4}

= \frac{2 5 - 5}{4}

= \frac{2 5 - 5}{4}

= \frac{2 5 - 5}{4}

= \frac{\frac{5 + 1}{4}}{\frac{2 5 - 5}{4}}

Simplify

\frac{\frac{5 + 1}{4}}{\frac{2 5 - 5}{4}} : \frac{( 3 10 + 5 2 ) 5 - 5}{20}

\frac{\frac{5 + 1}{4}}{\frac{2 5 - 5}{4}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 5 + 1 ) \cdot 4}{4 2 5 - 5}

Cancel the common factor:

4

= \frac{5 + 1}{2 5 - 5}

Rationalize

\frac{5 + 1}{2 5 - 5} : \frac{( 3 10 + 5 2 ) 5 - 5}{20}

\frac{5 + 1}{2 5 - 5}

Multiply by the conjugate

\frac{2}{2}

= \frac{( 5 + 1 ) 2}{2 5 - 5 2}

2 5 - 5 2 = 2 5 - 5

2 5 - 5 2

Apply radical rule:

a a = a

22 = 2

= 2 5 - 5

= \frac{2 ( 5 + 1 )}{2 5 - 5}

Multiply by the conjugate

\frac{5 - 5}{5 - 5}

= \frac{2 ( 5 + 1 ) 5 - 5}{2 5 - 5 5 - 5}

2 5 - 5 5 - 5 = 10 - 25

2 5 - 5 5 - 5

Apply radical rule:

a a = a

5 - 5 5 - 5 = 5 - 5

= 2 (5 - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 5, c = 5

= 2 \cdot 5 - 25

Multiply the numbers:

2 \cdot 5 = 10

= 10 - 25

= \frac{2 ( 5 + 1 ) 5 - 5}{10 - 2 5}

Factor out common term

- 2 : - 2 (5 - 5)

- 25 + 10

Rewrite

10

2 \cdot 5

= - 25 + 2 \cdot 5

Factor out common term

- 2

= - 2 (5 - 5)

= - \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )}

Cancel

- \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )} : \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )}

- \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )}

5 - 5 = - (5 - 5)

= - \frac{2 ( 1 + 5 ) 5 - 5}{- 2 ( 5 - 5 )}

Refine

= \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )}

= \frac{2 ( 5 + 1 ) 5 - 5}{2 ( 5 - 5 )}

Multiply by the conjugate

\frac{5 + 5}{5 + 5}

= \frac{2 ( 5 + 1 ) 5 - 5 ( 5 + 5 )}{2 ( 5 - 5 ) ( 5 + 5 )}

2 (5 + 1) 5 - 5 (5 + 5) = 610 5 - 5 + 102 5 - 5

2 (5 + 1) 5 - 5 (5 + 5)

= 2 (5 + 1) (5 + 5) 5 - 5

Expand

(5 + 1) (5 + 5) : 65 + 10

(5 + 1) (5 + 5)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 5, b = 1, c = 5, d = 5

= 5 \cdot 5 + 55 + 1 \cdot 5 + 1 \cdot 5

= 55 + 55 + 1 \cdot 5 + 1 \cdot 5

Simplify

55 + 55 + 1 \cdot 5 + 1 \cdot 5 : 65 + 10

55 + 55 + 1 \cdot 5 + 1 \cdot 5

Add similar elements:

55 + 1 \cdot 5 = 65

= 65 + 55 + 1 \cdot 5

Apply radical rule:

a a = a

55 = 5

= 65 + 5 + 1 \cdot 5

Multiply the numbers:

1 \cdot 5 = 5

= 65 + 5 + 5

Add the numbers:

5 + 5 = 10

= 65 + 10

= 65 + 10

= 2 5 - 5 (65 + 10)

Expand

2 5 - 5 (65 + 10) : 610 5 - 5 + 102 5 - 5

2 5 - 5 (65 + 10)

Apply the distributive law:

a (b + c) = ab + a c

a = 2 5 - 5, b = 65, c = 10

= 2 5 - 5 \cdot 65 + 2 5 - 5 \cdot 10

= 625 5 - 5 + 102 5 - 5

625 5 - 5 = 610 5 - 5

625 5 - 5

Apply radical rule:

a b = a \cdot b

25 5 - 5 = 2 \cdot 5 (5 - 5)

= 6 2 \cdot 5 (5 - 5)

Multiply the numbers:

2 \cdot 5 = 10

= 6 10 (5 - 5)

Apply radical rule:

assuming

a \geq 0, b \geq 0

10 (5 - 5) = 10 5 - 5

= 610 5 - 5

= 610 5 - 5 + 102 5 - 5

= 610 5 - 5 + 102 5 - 5

2 (5 - 5) (5 + 5) = 40

2 (5 - 5) (5 + 5)

Expand

(5 - 5) (5 + 5) : 20

(5 - 5) (5 + 5)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = 5, b = 5

= 5^{2} - (5)^{2}

Simplify

5^{2} - (5)^{2} : 20

5^{2} - (5)^{2}

5^{2} = 25

5^{2}

5^{2} = 25

= 25

(5)^{2} = 5

(5)^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (5^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 5^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 5

= 25 - 5

Subtract the numbers:

25 - 5 = 20

= 20

= 20

= 2 \cdot 20

Expand

2 \cdot 20 : 40

2 \cdot 20

Distribute parentheses

= 2 \cdot 20

Multiply the numbers:

2 \cdot 20 = 40

= 40

= 40

= \frac{6 10 5 - 5 + 10 2 5 - 5}{40}

Factor

610 5 - 5 + 102 5 - 5 : 2 5 - 5 (310 + 52)

610 5 - 5 + 102 5 - 5

Rewrite as

= 3 \cdot 2 5 - 5 10 + 5 \cdot 2 5 - 5 2

Factor out common term

2 5 - 5

= 2 5 - 5 (310 + 52)

= \frac{2 5 - 5 ( 3 10 + 5 2 )}{40}

Cancel the common factor:

2

= \frac{( 3 10 + 5 2 ) 5 - 5}{20}

= \frac{( 3 10 + 5 2 ) 5 - 5}{20}

= \frac{( 3 10 + 5 2 ) 5 - 5}{20}

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

Solve

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = \frac{( 3 10 + 5 2 ) 5 - 5}{20} : x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

Cross multiply

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

Simplify

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x} : \frac{0.2625 x}{1 - 0.0125 x ^{2}}

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x}

Add similar elements:

0.0625 x + 0.2 x = 0.2625 x

= \frac{0.2625 x}{1 - 0.0625 x \cdot 0.2 x}

Simplify

0.0625 x \cdot 0.2 x : 0.0125 x^{2}

0.0625 x \cdot 0.2 x

Multiply the numbers:

0.0625 \cdot 0.2 = 0.0125

= 0.0125 xx

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= 0.0125 x^{2}

= \frac{0.2625 x}{1 - 0.0125 x ^{2}}

\frac{0.2625 x}{1 - 0.0125 x ^{2}} = \frac{( 3 10 + 5 2 ) 5 - 5}{20}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

0.2625 x \cdot 20 = (1 - 0.0125 x^{2}) (310 + 52) 5 - 5

Simplify

0.2625 x \cdot 20 : 5.25 x

0.2625 x \cdot 20

Multiply the numbers:

0.2625 \cdot 20 = 5.25

= 5.25 x

5.25 x = (1 - 0.0125 x^{2}) (310 + 52) 5 - 5

5.25 x = (1 - 0.0125 x^{2}) (310 + 52) 5 - 5

Solve

5.25 x = (1 - 0.0125 x^{2}) (310 + 52) 5 - 5 : x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

5.25 x = (1 - 0.0125 x^{2}) (310 + 52) 5 - 5

Expand

(1 - 0.0125 x^{2}) (310 + 52) 5 - 5 : 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

(1 - 0.0125 x^{2}) (310 + 52) 5 - 5

= (310 + 52) 5 - 5 (1 - 0.0125 x^{2})

Expand

(1 - 0.0125 x^{2}) (310 + 52) : 310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2}

(1 - 0.0125 x^{2}) (310 + 52)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 1, b = - 0.0125 x^{2}, c = 310, d = 52

= 1 \cdot 310 + 1 \cdot 52 + (- 0.0125 x^{2}) \cdot 310 + (- 0.0125 x^{2}) \cdot 52

Apply minus-plus rules

+ (- a) = - a

= 1 \cdot 310 + 1 \cdot 52 - 310 \cdot 0.0125 x^{2} - 52 \cdot 0.0125 x^{2}

Simplify

1 \cdot 310 + 1 \cdot 52 - 310 \cdot 0.0125 x^{2} - 52 \cdot 0.0125 x^{2} : 310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2}

1 \cdot 310 + 1 \cdot 52 - 310 \cdot 0.0125 x^{2} - 52 \cdot 0.0125 x^{2}

1 \cdot 310 = 310

1 \cdot 310

Multiply the numbers:

1 \cdot 3 = 3

= 310

1 \cdot 52 = 52

1 \cdot 52

Multiply the numbers:

1 \cdot 5 = 5

= 52

310 \cdot 0.0125 x^{2} = 10 \cdot 0.0375 x^{2}

310 \cdot 0.0125 x^{2}

Multiply the numbers:

3 \cdot 0.0125 = 0.0375

= 10 \cdot 0.0375 x^{2}

52 \cdot 0.0125 x^{2} = 2 \cdot 0.0625 x^{2}

52 \cdot 0.0125 x^{2}

Multiply the numbers:

5 \cdot 0.0125 = 0.0625

= 2 \cdot 0.0625 x^{2}

= 310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2}

= 310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2}

= 5 - 5 (310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2})

Expand

5 - 5 (310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2}) : 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

5 - 5 (310 + 52 - 10 \cdot 0.0375 x^{2} - 2 \cdot 0.0625 x^{2})

Distribute parentheses

= 5 - 5 \cdot 310 + 5 - 5 \cdot 52 + 5 - 5 (- 10 \cdot 0.0375 x^{2}) + 5 - 5 (- 2 \cdot 0.0625 x^{2})

Apply minus-plus rules

+ (- a) = - a

= 310 5 - 5 + 52 5 - 5 - 10 \cdot 0.0375 5 - 5 x^{2} - 2 \cdot 0.0625 5 - 5 x^{2}

Simplify

310 5 - 5 + 52 5 - 5 - 10 \cdot 0.0375 5 - 5 x^{2} - 2 \cdot 0.0625 5 - 5 x^{2} : 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

310 5 - 5 + 52 5 - 5 - 10 \cdot 0.0375 5 - 5 x^{2} - 2 \cdot 0.0625 5 - 5 x^{2}

310 5 - 5 = 3 50 - 105

310 5 - 5

Apply radical rule:

a b = a \cdot b

10 5 - 5 = 10 (5 - 5)

= 3 10 (5 - 5)

Expand

10 (5 - 5) : 50 - 105

10 (5 - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = 10, b = 5, c = 5

= 10 \cdot 5 - 105

Multiply the numbers:

10 \cdot 5 = 50

= 50 - 105

= 3 50 - 105

52 5 - 5 = 5 10 - 25

52 5 - 5

Apply radical rule:

a b = a \cdot b

2 5 - 5 = 2 (5 - 5)

= 5 2 (5 - 5)

Expand

2 (5 - 5) : 10 - 25

2 (5 - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 5, c = 5

= 2 \cdot 5 - 25

Multiply the numbers:

2 \cdot 5 = 10

= 10 - 25

= 5 10 - 25

10 \cdot 0.0375 5 - 5 x^{2} = 0.0375 50 - 105 x^{2}

10 \cdot 0.0375 5 - 5 x^{2}

Apply radical rule:

a b = a \cdot b

10 5 - 5 = 10 (5 - 5)

= 0.0375 10 (5 - 5) x^{2}

Expand

10 (5 - 5) : 50 - 105

10 (5 - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = 10, b = 5, c = 5

= 10 \cdot 5 - 105

Multiply the numbers:

10 \cdot 5 = 50

= 50 - 105

= 0.0375 50 - 105 x^{2}

2 \cdot 0.0625 5 - 5 x^{2} = 0.0625 10 - 25 x^{2}

2 \cdot 0.0625 5 - 5 x^{2}

Apply radical rule:

a b = a \cdot b

2 5 - 5 = 2 (5 - 5)

= 0.0625 2 (5 - 5) x^{2}

Expand

2 (5 - 5) : 10 - 25

2 (5 - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 5, c = 5

= 2 \cdot 5 - 25

Multiply the numbers:

2 \cdot 5 = 10

= 10 - 25

= 0.0625 10 - 25 x^{2}

= 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

= 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

= 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

5.25 x = 3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2}

Switch sides

3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2} = 5.25 x

Move

5.25 x

to the left side

3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2} = 5.25 x

Subtract

5.25 x

from both sides

3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2} - 5.25 x = 5.25 x - 5.25 x

Simplify

3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2} - 5.25 x = 0

3 50 - 105 + 5 10 - 25 - 0.0375 50 - 105 x^{2} - 0.0625 10 - 25 x^{2} - 5.25 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 0.34409 \dots x^{2} - 5.25 x + 27.52763 \dots = 0

Solve with the quadratic formula

- 0.34409 \dots x^{2} - 5.25 x + 27.52763 \dots = 0

Quadratic Equation Formula:

For

a = - 0.34409 \dots, b = - 5.25, c = 27.52763 \dots

x_{1, 2} = \frac{- ( - 5.25 ) \pm ( - 5.25 ) ^{2} - 4 ( - 0.34409 \dots ) \cdot 27.52763 \dots}{2 ( - 0.34409 \dots )}

x_{1, 2} = \frac{- ( - 5.25 ) \pm ( - 5.25 ) ^{2} - 4 ( - 0.34409 \dots ) \cdot 27.52763 \dots}{2 ( - 0.34409 \dots )}

(- 5.25)^{2} - 4 (- 0.34409 \dots) \cdot 27.52763 \dots = 65.45104 \dots

(- 5.25)^{2} - 4 (- 0.34409 \dots) \cdot 27.52763 \dots

Apply rule

- (- a) = a

= (- 5.25)^{2} + 4 \cdot 0.34409 \dots \cdot 27.52763 \dots

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5.25)^{2} = 5.2 5^{2}

= 5.2 5^{2} + 4 \cdot 0.34409 \dots \cdot 27.52763 \dots

Multiply the numbers:

4 \cdot 0.34409 \dots \cdot 27.52763 \dots = 37.88854 \dots

= 5.2 5^{2} + 37.88854 \dots

5.2 5^{2} = 27.5625

= 27.5625 + 37.88854 \dots

Add the numbers:

27.5625 + 37.88854 \dots = 65.45104 \dots

= 65.45104 \dots

x_{1, 2} = \frac{- ( - 5.25 ) \pm 65.45104 \dots}{2 ( - 0.34409 \dots )}

Separate the solutions

x_{1} = \frac{- ( - 5.25 ) + 65.45104 \dots}{2 ( - 0.34409 \dots )}, x_{2} = \frac{- ( - 5.25 ) - 65.45104 \dots}{2 ( - 0.34409 \dots )}

x = \frac{- ( - 5.25 ) + 65.45104 \dots}{2 ( - 0.34409 \dots )} : - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}

\frac{- ( - 5.25 ) + 65.45104 \dots}{2 ( - 0.34409 \dots )}

Remove parentheses:

(- a) = - a, - (- a) = a

= \frac{5.25 + 65.45104 \dots}{- 2 \cdot 0.34409 \dots}

Multiply the numbers:

2 \cdot 0.34409 \dots = 0.68819 \dots

= \frac{5.25 + 65.45104 \dots}{- 0.68819 \dots}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}

x = \frac{- ( - 5.25 ) - 65.45104 \dots}{2 ( - 0.34409 \dots )} : \frac{65.45104 \dots - 5.25}{0.68819 \dots}

\frac{- ( - 5.25 ) - 65.45104 \dots}{2 ( - 0.34409 \dots )}

Remove parentheses:

(- a) = - a, - (- a) = a

= \frac{5.25 - 65.45104 \dots}{- 2 \cdot 0.34409 \dots}

Multiply the numbers:

2 \cdot 0.34409 \dots = 0.68819 \dots

= \frac{5.25 - 65.45104 \dots}{- 0.68819 \dots}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

5.25 - 65.45104 \dots = - (65.45104 \dots - 5.25)

= \frac{65.45104 \dots - 5.25}{0.68819 \dots}

The solutions to the quadratic equation are:

x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

Verify Solutions

Find undefined (singularity) points:

x = 45, x = - 45

Take the denominator(s) of

\frac{0.0625 x + 0.2 x}{1 - 0.0625 x \cdot 0.2 x}

and compare to zero

Solve

1 - 0.0625 x \cdot 0.2 x = 0 : x = 45, x = - 45

1 - 0.0625 x \cdot 0.2 x = 0

Move

1

to the right side

1 - 0.0625 x \cdot 0.2 x = 0

Subtract

1

from both sides

1 - 0.0625 x \cdot 0.2 x - 1 = 0 - 1

Simplify

- 0.0625 x \cdot 0.2 x = - 1

- 0.0625 x \cdot 0.2 x = - 1

Simplify

- 0.0125 x^{2} = - 1

Divide both sides by

- 0.0125

\frac{- 0.0125 x ^{2}}{- 0.0125} = \frac{- 1}{- 0.0125}

x^{2} = \frac{1}{0.0125}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{0.0125}, x = - \frac{1}{0.0125}

\frac{1}{0.0125} = 45

\frac{1}{0.0125}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{0.0125}

Apply radical rule:

1 = 1

1 = 1

= \frac{1}{0.0125}

0.0125 = \frac{1}{4 5}

0.0125

0.0125 = \frac{1}{80}

0.0125

Multiply and divide by 10 for every number after the decimal point.

There are

4

digits to the right of the decimal point, therefore multiply and divide by

10000

= \frac{10000 \cdot 0.0125}{10000}

Multiply the numbers:

10000 \cdot 0.0125 = 125

= \frac{125}{10000}

Cancel the numbers:

\frac{125}{10000} = \frac{1}{80}

= \frac{1}{80}

= \frac{1}{80}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{80}

Apply radical rule:

1 = 1

1 = 1

= \frac{1}{80}

80 = 45

80

Prime factorization of

80 : 2^{4} \cdot 5

80

80

divides by

280 = 40 \cdot 2

= 2 \cdot 40

40

divides by

240 = 20 \cdot 2

= 2 \cdot 2 \cdot 20

20

divides by

220 = 10 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 5

= 2^{4} \cdot 5

= 2^{4} \cdot 5

Apply radical rule:

ab = a b, a \geq 0, b \geq 0

2^{4} \cdot 5 = 2^{4} 5

= 2^{4} 5

2^{4} = 4

2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}}

= 2^{\frac{4}{2}}

Divide the numbers:

\frac{4}{2} = 2

= 2^{2}

2^{2} = 4

= 4

= 45

= \frac{1}{4 5}

= \frac{1}{\frac{1}{4 5}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{4 5}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 45

- \frac{1}{0.0125} = - 45

- \frac{1}{0.0125}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= - \frac{1}{0.0125}

Apply radical rule:

1 = 1

1 = 1

= - \frac{1}{0.0125}

0.0125 = \frac{1}{4 5}

0.0125

0.0125 = \frac{1}{80}

0.0125

Multiply and divide by 10 for every number after the decimal point.

There are

4

digits to the right of the decimal point, therefore multiply and divide by

10000

= \frac{10000 \cdot 0.0125}{10000}

Multiply the numbers:

10000 \cdot 0.0125 = 125

= \frac{125}{10000}

Cancel the numbers:

\frac{125}{10000} = \frac{1}{80}

= \frac{1}{80}

= \frac{1}{80}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{80}

Apply radical rule:

1 = 1

1 = 1

= \frac{1}{80}

80 = 45

80

Prime factorization of

80 : 2^{4} \cdot 5

80

80

divides by

280 = 40 \cdot 2

= 2 \cdot 40

40

divides by

240 = 20 \cdot 2

= 2 \cdot 2 \cdot 20

20

divides by

220 = 10 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 10

10

divides by

210 = 5 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 5

2, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 5

= 2^{4} \cdot 5

= 2^{4} \cdot 5

Apply radical rule:

ab = a b, a \geq 0, b \geq 0

2^{4} \cdot 5 = 2^{4} 5

= 2^{4} 5

2^{4} = 4

2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}}

= 2^{\frac{4}{2}}

Divide the numbers:

\frac{4}{2} = 2

= 2^{2}

2^{2} = 4

= 4

= 45

= \frac{1}{4 5}

= - \frac{1}{\frac{1}{4 5}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

\frac{1}{\frac{1}{4 5}} = \frac{4 5}{1}

= - \frac{4 5}{1}

Apply the fraction rule:

\frac{a}{1} = a

= - 45

x = 45, x = - 45

The following points are undefined

x = 45, x = - 45

Combine undefined points with solutions:

x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}, x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

Verify solutions by plugging them into the original equation

Check the solutions by plugging them into

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

Remove the ones that don't agree with the equation.

Check the solution

- \frac{5.25 + 65.45104 \dots}{0.68819 \dots} :

False

- \frac{5.25 + 65.45104 \dots}{0.68819 \dots}

Plug in

n = 1

- \frac{5.25 + 65.45104 \dots}{0.68819 \dots}

For

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

plug in

x = - \frac{5.25 + 65.45104 \dots}{0.68819 \dots}

arctan (0.0625 (- \frac{5.25 + 65.45104 \dots}{0.68819 \dots})) + arctan (0.2 (- \frac{5.25 + 65.45104 \dots}{0.68819 \dots})) = 5 4^{\circ}

Refine

- 2.19911 \dots = 0.94247 \dots

\Rightarrow False

Check the solution

\frac{65.45104 \dots - 5.25}{0.68819 \dots} :

True

\frac{65.45104 \dots - 5.25}{0.68819 \dots}

Plug in

n = 1

\frac{65.45104 \dots - 5.25}{0.68819 \dots}

For

arctan (0.0625 x) + arctan (0.2 x) = 5 4^{\circ}

plug in

x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

arctan (0.0625 \cdot \frac{65.45104 \dots - 5.25}{0.68819 \dots}) + arctan (0.2 \cdot \frac{65.45104 \dots - 5.25}{0.68819 \dots}) = 5 4^{\circ}

Refine

0.94247 \dots = 0.94247 \dots

\Rightarrow True

x = \frac{65.45104 \dots - 5.25}{0.68819 \dots}

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Frequently Asked Questions (FAQ)

What is the general solution for arctan(0.0625x)+arctan(0.2x)=54 ?
The general solution for arctan(0.0625x)+arctan(0.2x)=54 is x=(sqrt(65.45104…)-5.25)/(0.68819…)