What is the general solution for cos(θ)-sin(θ)=sqrt(2) ?

The general solution for cos(θ)-sin(θ)=sqrt(2) is θ=(7pi)/4+2pin

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cos(θ)-sin(θ)=sqrt(2)

Solution

cos (θ) - sin (θ) = 2

Solution

θ = \frac{7 π}{4} + 2 πn

Degrees

θ = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) - sin (θ) = 2

Subtract

2

from both sides

cos (θ) - sin (θ) - 2 = 0

Rewrite using trig identities

cos (θ) - sin (θ) - 2

Use the following identity:

sin (x) = cos (\frac{π}{2} - x)

= cos (θ) - cos (\frac{π}{2} - θ) - 2

Use the Sum to Product identity:

cos (s) - cos (t) = - 2 sin (\frac{s + t}{2}) sin (\frac{s - t}{2})

= - 2 - 2 sin (\frac{θ + \frac{π}{2} - θ}{2}) sin (\frac{θ - ( \frac{π}{2} - θ )}{2})

2 sin (\frac{θ + \frac{π}{2} - θ}{2}) sin (\frac{θ - ( \frac{π}{2} - θ )}{2}) = 2 sin (\frac{4 θ - π}{4})

2 sin (\frac{θ + \frac{π}{2} - θ}{2}) sin (\frac{θ - ( \frac{π}{2} - θ )}{2})

\frac{θ + \frac{π}{2} - θ}{2} = \frac{π}{4}

\frac{θ + \frac{π}{2} - θ}{2}

θ + \frac{π}{2} - θ = \frac{π}{2}

θ + \frac{π}{2} - θ

Group like terms

= θ - θ + \frac{π}{2}

Add similar elements:

θ - θ = 0

= \frac{π}{2}

= \frac{\frac{π}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{π}{4}

= 2 sin (\frac{π}{4}) sin (\frac{θ - ( - θ + \frac{π}{2} )}{2})

\frac{θ - ( \frac{π}{2} - θ )}{2} = \frac{4 θ - π}{4}

\frac{θ - ( \frac{π}{2} - θ )}{2}

Expand

θ - (\frac{π}{2} - θ) : 2 θ - \frac{π}{2}

θ - (\frac{π}{2} - θ)

- (\frac{π}{2} - θ) : - \frac{π}{2} + θ

- (\frac{π}{2} - θ)

Distribute parentheses

= - (\frac{π}{2}) - (- θ)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - \frac{π}{2} + θ

= θ - \frac{π}{2} + θ

Simplify

θ - \frac{π}{2} + θ : 2 θ - \frac{π}{2}

θ - \frac{π}{2} + θ

Group like terms

= θ + θ - \frac{π}{2}

Add similar elements:

θ + θ = 2 θ

= 2 θ - \frac{π}{2}

= 2 θ - \frac{π}{2}

= \frac{2 θ - \frac{π}{2}}{2}

Join

2 θ - \frac{π}{2} : \frac{4 θ - π}{2}

2 θ - \frac{π}{2}

Convert element to fraction:

2 θ = \frac{2 θ 2}{2}

= \frac{2 θ \cdot 2}{2} - \frac{π}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 θ \cdot 2 - π}{2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{4 θ - π}{2}

= \frac{\frac{4 θ - π}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 θ - π}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{4 θ - π}{4}

= 2 sin (\frac{π}{4}) sin (\frac{4 θ - π}{4})

Simplify

sin (\frac{π}{4}) : \frac{2}{2}

sin (\frac{π}{4})

Use the following trivial identity:

sin (\frac{π}{4}) = \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= 2 \cdot \frac{2}{2} sin (\frac{4 θ - π}{4})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 2 sin ( \frac{4 θ - π}{4} )}{2}

Cancel the common factor:

2

= 2 sin (\frac{4 θ - π}{4})

= - 2 - 2 sin (\frac{4 θ - π}{4})

- 2 - 2 sin (\frac{4 θ - π}{4}) = 0

Move

2

to the right side

- 2 - 2 sin (\frac{4 θ - π}{4}) = 0

Add

2

to both sides

- 2 - 2 sin (\frac{4 θ - π}{4}) + 2 = 0 + 2

Simplify

- 2 sin (\frac{4 θ - π}{4}) = 2

- 2 sin (\frac{4 θ - π}{4}) = 2

Divide both sides by

- 2

- 2 sin (\frac{4 θ - π}{4}) = 2

Divide both sides by

- 2

\frac{- 2 sin ( \frac{4 θ - π}{4} )}{- 2} = \frac{2}{- 2}

Simplify

sin (\frac{4 θ - π}{4}) = - 1

sin (\frac{4 θ - π}{4}) = - 1

General solutions for

sin (\frac{4 θ - π}{4}) = - 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{4 θ - π}{4} = \frac{3 π}{2} + 2 πn

\frac{4 θ - π}{4} = \frac{3 π}{2} + 2 πn

Solve

\frac{4 θ - π}{4} = \frac{3 π}{2} + 2 πn : θ = \frac{7 π}{4} + 2 πn

\frac{4 θ - π}{4} = \frac{3 π}{2} + 2 πn

Multiply both sides by

4

\frac{4 θ - π}{4} = \frac{3 π}{2} + 2 πn

Multiply both sides by

4

\frac{4 ( 4 θ - π )}{4} = 4 \cdot \frac{3 π}{2} + 4 \cdot 2 πn

Simplify

\frac{4 ( 4 θ - π )}{4} = 4 \cdot \frac{3 π}{2} + 4 \cdot 2 πn

Simplify

\frac{4 ( 4 θ - π )}{4} : 4 θ - π

\frac{4 ( 4 θ - π )}{4}

Divide the numbers:

\frac{4}{4} = 1

= 4 θ - π

Simplify

4 \cdot \frac{3 π}{2} + 4 \cdot 2 πn : 6 π + 8 πn

4 \cdot \frac{3 π}{2} + 4 \cdot 2 πn

4 \cdot \frac{3 π}{2} = 6 π

4 \cdot \frac{3 π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 4}{2}

Multiply the numbers:

3 \cdot 4 = 12

= \frac{12 π}{2}

Divide the numbers:

\frac{12}{2} = 6

= 6 π

4 \cdot 2 πn = 8 πn

4 \cdot 2 πn

Multiply the numbers:

4 \cdot 2 = 8

= 8 πn

= 6 π + 8 πn

4 θ - π = 6 π + 8 πn

4 θ - π = 6 π + 8 πn

4 θ - π = 6 π + 8 πn

Move

π

to the right side

4 θ - π = 6 π + 8 πn

Add

π

to both sides

4 θ - π + π = 6 π + 8 πn + π

Simplify

4 θ = 7 π + 8 πn

4 θ = 7 π + 8 πn

Divide both sides by

4

4 θ = 7 π + 8 πn

Divide both sides by

4

\frac{4 θ}{4} = \frac{7 π}{4} + \frac{8 πn}{4}

Simplify

θ = \frac{7 π}{4} + 2 πn

θ = \frac{7 π}{4} + 2 πn

θ = \frac{7 π}{4} + 2 πn

Popular Examples

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3 sin (2 x + 30) = tan (2 x + 30)

cos^3(x)= 5/8

cos^{3} (x) = \frac{5}{8}

cos(30+u)=0.82

cos (3 0^{\circ} + u) = 0.82

16sin(t)cos(t)=4sin(t)

16 sin (t) cos (t) = 4 sin (t)

4cos(x)=4-4cos(x)

4 cos (x) = 4 - 4 cos (x)

Frequently Asked Questions (FAQ)

What is the general solution for cos(θ)-sin(θ)=sqrt(2) ?
The general solution for cos(θ)-sin(θ)=sqrt(2) is θ=(7pi)/4+2pin