What is the general solution for cos(θ)=-(2sqrt(5))/5 ?

The general solution for cos(θ)=-(2sqrt(5))/5 is θ=2.67794…+2pin,θ=-2.67794…+2pin

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cos(θ)=-(2sqrt(5))/5

cos (θ) = - \frac{2 5}{5}

θ = 2.67794 \dots + 2 πn, θ = - 2.67794 \dots + 2 πn

Degrees

θ = 153.43494 \dots^{\circ} + 36 0^{\circ} n, θ = - 153.43494 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{2 5}{5}

Apply trig inverse properties

cos (θ) = - \frac{2 5}{5}

General solutions for

cos (θ) = - \frac{2 5}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{2 5}{5}) + 2 πn, θ = - arccos (- \frac{2 5}{5}) + 2 πn

θ = arccos (- \frac{2 5}{5}) + 2 πn, θ = - arccos (- \frac{2 5}{5}) + 2 πn

Show solutions in decimal form

θ = 2.67794 \dots + 2 πn, θ = - 2.67794 \dots + 2 πn

cos (2 a) + cos (a) = 0

536 = 100 + 759 \cdot tan (x)

cos^{2} (x) = cos^{2} (x) csc (x)

tan (α) = - 1

sin (3 π x) = 1

What is the general solution for cos(θ)=-(2sqrt(5))/5 ?
The general solution for cos(θ)=-(2sqrt(5))/5 is θ=2.67794…+2pin,θ=-2.67794…+2pin